#include #define rep(i,n) for (int i = 0; i < (n); i++) using namespace std; using ll = long long; using P = pair; const int mod = 1000000007; struct mint { ll x; // typedef long long ll; mint(ll x=0):x((x%mod+mod)%mod){} mint operator-() const { return mint(-x);} mint& operator+=(const mint a) { if ((x += a.x) >= mod) x -= mod; return *this; } mint& operator-=(const mint a) { if ((x += mod-a.x) >= mod) x -= mod; return *this; } mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;} mint operator+(const mint a) const { return mint(*this) += a;} mint operator-(const mint a) const { return mint(*this) -= a;} mint operator*(const mint a) const { return mint(*this) *= a;} mint pow(ll t) const { if (!t) return 1; mint a = pow(t>>1); a *= a; if (t&1) a *= *this; return a; } // for prime mod mint inv() const { return pow(mod-2);} mint& operator/=(const mint a) { return *this *= a.inv();} mint operator/(const mint a) const { return mint(*this) /= a;} }; istream& operator>>(istream& is, mint& a) { return is >> a.x;} ostream& operator<<(ostream& os, const mint& a) { return os << a.x;} vector mul(vector> a, vector v){ int n=v.size(); vector ans(n); rep(i, n) rep(k, n){ ans[i]+=a[i][k]*v[k]; } return ans; } vector> mulmat(vector> a, vector> b){ int n=a[0].size(); vector> ans(n, vector(n)); rep(i, n) rep(j, n) rep(k, n){ ans[i][j]+=a[i][k]*b[k][j]; } return ans; } int main(){ int n, k, l; cin>>n>>k>>l; vector dp(n); dp[0]=1; vector> mat(n, vector(n)), dmat; rep(i, n) for(int j=1; j<=l; j++){ mat[i][(i-j+n)%n]=1; } for(int x=k; x>0; x>>=1){ if(x&1) dp=mul(mat, dp); mat=mulmat(mat, mat); } rep(i, n) cout<