import sys sys.setrecursionlimit(10**7) from collections import defaultdict class UnionFind(object): def __init__(self, n=1): self.par = [i for i in range(n)] self.rank = [0 for _ in range(n)] self.size = [1 for _ in range(n)] def find(self, x): """ x が属するグループを探索して親を出す。 """ if self.par[x] == x: return x else: self.par[x] = self.find(self.par[x]) return self.par[x] def union(self, x, y): """ x と y のグループを結合 """ x = self.find(x) y = self.find(y) if x != y: if self.rank[x] < self.rank[y]: x, y = y, x if self.rank[x] == self.rank[y]: self.rank[x] += 1 self.par[y] = x self.size[x] += self.size[y] def is_same(self, x, y): """ x と y が同じグループか否か """ return self.find(x) == self.find(y) def get_size(self, x): """ x が属するグループの要素数 """ x = self.find(x) return self.size[x] def SCC(N, G, RG): order = [] used = [0]*N group = [None]*N def dfs(s): used[s] = 1 for t in G[s]: if not used[t]: dfs(t) order.append(s) def rdfs(s, col): #print(s) group[s] = col used[s] = 1 for t in RG[s]: if not used[t]: rdfs(t, col) TS.append(s) for i in range(N): if not used[i]: dfs(i) used = [0]*N label = 0 TSL = [] for s in reversed(order): if not used[s]: TS = [] rdfs(s, label) #TS.reverse() TSL.append(TS) label += 1 return label, group, TSL def main(): N,M = map(int,input().split()) Q = [] S = set([]) for i in range(M): U,V = map(int,input().split()) Q.append((U,V)) S.add(U) S.add(V) L = list(S) n = len(S) #出てくる頂点の種類 L.sort() dic = {} #元の番号→座圧後の番号 revdic = {} #座圧後の番号→元の番号 for i in range(n): dic[L[i]] = i revdic[i] = L[i] ALL = [i for i in range(n)] ALL = set(ALL) G = [[] for _ in range(n)] RG = [[] for _ in range(n)] uf = UnionFind(n) for u,v in Q: uz = dic[u] vz = dic[v] G[uz].append(vz) RG[vz].append(uz) uf.union(uz,vz) #print(G) unidic = defaultdict(list) for i in range(n): par = uf.find(i) unidic[par].append(i) #print(unidic) #連結成分ごとにSCC ans = [] #for L in unidic.values(): LIST, Group, TT = SCC(n, G, RG) #print(LIST,Group,TT) prepar = -1 for i,group in enumerate(TT): nowpar = uf.find(group[0]) #print(i,prepar,nowpar) if i != 0 and prepar == nowpar: #一番初めではないし、今見てる塊が前とつながっている。 pre = TT[i-1][0] oripre = revdic[pre] first = group[0] orifirst = revdic[first] ans.append([oripre, orifirst]) else: prepar = nowpar if len(group) == 1: continue #一つだったらつなげる必要なし for j in range(len(group)): if j < len(group) - 1: s = group[j]; t = group[j+1] else: s = group[j]; t = group[0] oris = revdic[s]; orit = revdic[t] ans.append([oris, orit]) print(len(ans)) for ret in ans: print(*ret) if __name__ == '__main__': main()