# n以上の素数で最小のものを返す def eratosthenes0(n): nu=n+min(n,10**6) kouho=set(range(n,nu)) for x in range(2,int(nu**.5)+1): xx=x*(n//x) while xxy0:x0,y0=y0,x0 x1=eratosthenes0(x0) y1=eratosthenes0(y0) if x0==1 and y0==1: return False elif x0==1 or y0==1: # x0が1 y1=eratosthenes0(y0+1) # y0より真に大きい素数 if (y1-y0)%2==0: return True else: return False elif x0==2 or y0==2: # (2,8)->(2,9) ng # (2,8)->(3,8) ng return False elif x0==x1 and y0==y1: return False elif x0==x1 or y0==y1: # 素数の座標を動かす if x0==x1: return not main(x0+1,y0) else: return not main(x0,y0+1) else: if (x1-x0)+(y1-y0) % 2 == 0: return True else: return False if __name__=='__main__': x,y=map(int,input().split()) ret=main(x,y) if ret: print("First") else: print("Second")