import sys
from collections import defaultdict, Counter, deque
from itertools import permutations, combinations, product, combinations_with_replacement, groupby, accumulate
import operator
from math import sqrt, gcd, factorial
# from math import isqrt, prod,comb  # python3.8用(notpypy)
#from bisect import bisect_left,bisect_right
#from functools import lru_cache,reduce
#from heapq import heappush,heappop,heapify,heappushpop,heapreplace
#import numpy as np
#import networkx as nx
#from networkx.utils import UnionFind
#from numba import njit, b1, i1, i4, i8, f8
#from scipy.sparse import csr_matrix
#from scipy.sparse.csgraph import shortest_path, floyd_warshall, dijkstra, bellman_ford, johnson, NegativeCycleError
# numba例 @njit(i1(i4[:], i8[:, :]),cache=True) 引数i4配列、i8 2次元配列,戻り値i1
def input(): return sys.stdin.readline().rstrip()
def divceil(n, k): return 1+(n-1)//k  # n/kの切り上げを返す
def yn(hantei, yes='Yes', no='No'): print(yes if hantei else no)


def main():
    mod = 10**9+7
    mod2 = 998244353
    n, m, k = map(int, input().split())
    A = list(map(int, input().split()))
    cost = [[float("inf")]*n for i in range(n)]
    for i in range(m):
        x, y, z = map(int, input().split())
        x -= 1
        y -= 1
        cost[x][y] = z
        cost[y][x] = z

    for i in range(n):
        cost[i][i] = 0

    for kk in range(n):
        for ii in range(n):
            for jj in range(n):
                cost[ii][jj] = min(cost[ii][jj], cost[ii][kk] + cost[kk][jj])
    ans = 10**12
    dp = [10**12]*2**n
    dp[0] == 0
    popcnt = [0]*2**n
    for bit in range(1, 2**n):
        popcnt[bit] = popcnt[bit ^ (bit & (-bit))]+1
        if 2 <= popcnt[bit] <= k:
            for i in range(n):
                if bit & 2**i:
                    for j in range(i+1, n):
                        if bit & 2**j:
                            dp[bit] = min(
                                A[i]+cost[i][j]+dp[bit ^ (2**i)], A[j]+cost[i][j]+dp[bit ^ (2**j)], dp[bit])
            if popcnt[bit]==k and ans > dp[bit]:
                ans=dp[bit]
        elif popcnt[bit]==1:
            for i in range(n):
                if bit & 2**i:
                    dp[bit]=A[i]
    print(ans)


if __name__ == '__main__':
    main()