#include using std::cin; using std::cout; using std::istream; using std::ostream; using ll = long long; // const int mod = 998244353; const int mod = 1000000007; struct mint { ll x; mint(ll x=0):x((x%mod+mod)%mod) {} mint operator-() const { return mint(-x); } mint& operator+=(const mint a) { if ((x += a.x) >= mod) x -= mod; return *this; } mint& operator-=(const mint a) { if ((x += mod-a.x) >= mod) x -= mod; return *this; } mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this; } mint operator+(const mint a) const { return mint(*this) += a; } mint operator-(const mint a) const { return mint(*this) -= a; } mint operator*(const mint a) const { return mint(*this) *= a; } mint pow(ll t) const { if (!t) return 1; mint a = pow(t>>1); a *= a; if (t&1) a *= *this; return a; } // for prime mod mint inv() const { return pow(mod-2); } mint& operator/=(const mint a) { return *this *= a.inv(); } mint operator/(const mint a) const { return mint(*this) /= a; } }; istream& operator>>(istream& is, mint& a) { return is >> a.x; } ostream& operator<<(ostream& os, const mint& a) { return os << a.x; } ll qmi(ll m, ll k, ll p) { int res = 1 % p, t = m; while (k) { if (k&1) res = res * t % p; t = t * t % p; k >>= 1; } return res; } int main() { ll a, b, c, k; cin >> a >> b >> c >> k; ll ok = 0; if (k >= 31) ok = mod - 1; k = qmi(2, k, mod) + ok; ll ans = qmi(a, k, mod) % mod * qmi(b, k, mod) % mod * qmi(c, k, mod) % mod; cout << ans % (mod - 1) << '\n'; return 0; }