#include using std::cin; using std::cout; using std::istream; using std::ostream; using std::string; using ll = long long; // const int mod = 998244353; const int mod = 1000000007; struct mint { ll x; mint(ll x=0):x((x%mod+mod)%mod) {} mint operator-() const { return mint(-x); } mint& operator+=(const mint a) { if ((x += a.x) >= mod) x -= mod; return *this; } mint& operator-=(const mint a) { if ((x += mod-a.x) >= mod) x -= mod; return *this; } mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this; } mint operator+(const mint a) const { return mint(*this) += a; } mint operator-(const mint a) const { return mint(*this) -= a; } mint operator*(const mint a) const { return mint(*this) *= a; } mint pow(ll t) const { if (!t) return 1; mint a = pow(t>>1); a *= a; if (t&1) a *= *this; return a; } // for prime mod mint inv() const { return pow(mod-2); } mint& operator/=(const mint a) { return *this *= a.inv(); } mint operator/(const mint a) const { return mint(*this) /= a; } }; istream& operator>>(istream& is, mint& a) { return is >> a.x; } ostream& operator<<(ostream& os, const mint& a) { return os << a.x; } int main() { int a; string b; cin >> a >> b; int n = b.size(); reverse(b.begin(), b.end()); mint ans, mul = 1, t; for (int i = 0; i < n; ++i) { ans -= mul - 1; t += mint(b[i] - '0') * mul; mul *= a; } ans += t * n; ans -= t; cout << ans << '\n'; return 0; }