#include #include #include #include using namespace std; int N, A[5009], R[5009]; double dp[5009][5009]; vector> vec; double solve(int Border) { for (int i = 0; i <= N; i++) { for (int j = 0; j <= N; j++) dp[i][j] = 0; } dp[0][0] = 1.0; for (int i = 0; i < N; i++) { for (int j = 0; j <= N; j++) { if (A[i + 1] > Border) { dp[i + 1][max(0, j - 1)] += dp[i][j] / 2.0; dp[i + 1][j] += dp[i][j] / 2.0; } else { dp[i + 1][j + 1] += dp[i][j] / 2.0; dp[i + 1][j] += dp[i][j] / 2.0; } } } double ret = 0; for (int i = 1; i <= N; i++) { if (A[i] <= Border) continue; ret += 1.0 * R[i] * dp[i - 1][0]; } return ret / 2.0; } int main() { // Step #1. Input cin >> N; for (int i = 1; i <= N; i++) cin >> A[i]; for (int i = 1; i <= N; i++) cin >> R[i]; assert(1 <= N && N <= 500); for (int i = 1; i <= N; i++) assert(1 <= A[i] && A[i] <= 1000); for (int i = 1; i <= N; i++) assert(1 <= R[i] && R[i] <= 1000); // Step #2. Sorting vec.push_back(make_pair(0, 0)); for (int i = 1; i <= N; i++) vec.push_back(make_pair(A[i], i)); sort(vec.begin(), vec.end()); // Step #3. BruteForce double Answer = 0; for (int i = 0; i < N; i++) { if (vec[i].first == vec[i + 1].first) continue; double S1 = solve(vec[i].first); double S2 = 1.0 * (vec[i + 1].first - vec[i].first); Answer += S1 * S2; } printf("%.12lf\n", Answer * 1.0000001); return 0; }