def sqrt(n, k = 3):
    if n == 0: return 0
    l = k - 1
    if not n: return 0
    y = 1 << (n.bit_length() + l) // k
    x = y + 1
    while y < x:
        x = y
        y = (l * x + n // (x ** l)) // k
    return x

N = int(input())
print("Yes" if sqrt(N) ** 3 == N else "No")