n = int(input())

import numpy as np

a = np.zeros((n, n))

sump =[i for i in range(n // 2, 2 * n - n // 2)]
sums =[i for i in range(0, n // 2)] + [i for i in range(2 * n - n // 2, 2 * n)]
for i in range(n - 1, -1, -1):
    for j in range(n - 1, -1, -1):
        if sums[i] >= 2 and sump[j] >= 2:
            a[i][j] = 2
            sums[i] -= 2
            sump[j] -= 2
        elif sums[i] >= 1 and sump[j] >= 1:
            a[i][j] = 1
            sums[i] -= 1
            sump[j] -= 1
for i in range(n):
    for j in range(n):
        print(int(a[i][j]), end = ' ')
    print()