//想定解は周期性だと思うが、行列累乗で殴ります。 #include #include #include #include #include #include #include #include #include #include #include #include #define int long long #define rep(i, n) for(i = 0; i < n; i++) using namespace std; typedef vector Array; typedef vector Mat; const int mod = 10; Mat ident(int n) { Mat ret(n, Array(n)); int i; rep(i, n) ret[i][i] = 1; return ret; } Mat mul(Mat a, Mat b) { int n = a.size(); int m = b[0].size(); Mat ret(n, Array(m)); for (int i = 0; i < n; i++) { for (int j = 0; j < m; j++) { for (int k = 0; k < a[0].size(); k++) { ret[i][j] += a[i][k] * b[k][j]; ret[i][j] %= mod; } } } return ret; } Mat powmat(Mat a, int n) { if (n == 0) return ident(a.size()); if (n % 2 == 0) return powmat(mul(a, a), n / 2); return mul(a, powmat(a, n - 1)); } //Ab (bは縦ベクトル) Array mul(Mat a, Array b) { Array ret(a.size()); for (int i = 0; i < a.size(); i++) { for (int j = 0; j < b.size(); j++) { ret[i] += a[i][j] * b[j]; ret[i] %= mod; } } return ret; } signed main() { int p, q, r, K; cin >> p >> q >> r >> K; p %= 10; q %= 10; r %= 10; Mat mat = {{0, 1, 0}, {0, 0, 1}, {1, 1, 1}}; Array ini = {{p, q, r}}; Mat m = powmat(mat, K - 1); Array res = mul(m, ini); cout << res[0] << endl; return 0; }