/*** author: yuji9511 ***/ #include // #include // using namespace atcoder; using namespace std; using ll = long long; using lpair = pair; using vll = vector; const ll MOD = 1e9+7; const ll INF = 1e18; #define rep(i,m,n) for(ll i=(m);i<(n);i++) #define rrep(i,m,n) for(ll i=(m);i>=(n);i--) ostream& operator<<(ostream& os, lpair& h){ os << "(" << h.first << ", " << h.second << ")"; return os;} #define printa(x,n) for(ll i=0;i void print(H&& h, T&&... t){cout<(t)...);} templatebool chmax(T &a, const T &b) { if (abool chmin(T &a, const T &b) { if (b> N >> M; vll t(M), x(M), y(M); rep(i,0,M) cin >> t[i] >> x[i] >> y[i]; Combination cb(400010); ll ans = cb.nck(2*N, N) * 2 * N % MOD; rep(i,0,M){ if(t[i] == 1){ ans -= cb.nck(x[i]+y[i], x[i]) * cb.nck(2*N-x[i]-y[i]-1, N-y[i]) % MOD; ans = (ans + 2*MOD) % MOD; }else{ ans -= cb.nck(x[i]+y[i], x[i]) * cb.nck(2*N-x[i]-y[i]-1, N-x[i]) % MOD; ans = (ans + 2*MOD) % MOD; } } print(ans); } int main(){ cin.tie(0); ios::sync_with_stdio(false); solve(); }