#include <iostream>
#include <string>
using namespace std;
#include <algorithm>
#include <vector>
#include <cstdio>
#include <cstdlib>
#include <cmath>
#include <cstring>
#include <iomanip>
#include <set>
#include <map>
#include <queue>
#include <cassert>
using ll = long long;
using ld = long double;
const ll MOD1 = 1000000007;
const ll MOD2 = 998244353;
const ll LIMIT1 = 200010;
const ll LIMIT2 = 500010;
const ll LIMIT3 = 1000010;
const int INF = ((1<<30)-1);
const ll LLINF = (1LL<<60);
const ld EPS = (1e-14);
using cv = const void;
using P = pair<ll,ll>;
#define rep(i,n) for((i)=0;(i)<(n);(i)++)
#define per(i,n) for((i)=(n)-1;(i)>=0;(i)--)
#define ALL(a) (a).begin(),(a).end()
#define ALL2(a, n) (a),(a)+(n)
template<class T,class C> T max(T a,C b){ return std::max(a, (T)b); }
template<class T,class C> T min(T a,C b){ return std::min(a, (T)b); }
template<class T,class C> bool chmax(T &a,const C b){ if(a<(T)b){ a=(T)b;return true; } return false; }
template<class T,class C> bool chmin(T &a,const C b){ if((T)b<a){ a=(T)b;return true; } return false; }
#define zt(a,b) (max((a),(b))-min((a),(b)))
#define setpre(n) fixed << setprecision(n)
ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}
ll lcm(ll a,ll b){return (a/gcd(a,b))*b;}
#define YES(b) (b?"YES":"NO")
#define Yes(b) (b?"Yes":"No")
#define yes(b) (b?"yes":"no")
template<class T,class C> char gl(const T a,const C b){
  T bb = (T)b;
  if(a<bb) return '<';
  else if(a>bb) return '>';
  else return '=';
}
int dx[8]={1,0,-1,0,1,-1,-1,1},dy[8]={0,1,0,-1,1,1,-1,-1};
ll modpow(ll a, ll n, ll mod) {
  ll res = 1;
  while (n > 0) {
    if (n & 1){
      res *= a; if(mod>=1) res %= mod;
    }
    a *= a; if(mod>=1) a %= mod;
    n >>= 1;
  }
  return res;
}
void initialize(){
  
}
ll dfs(vector<ll> &e, ll i,ll a,ll b,ll c){
  if(i==e.size()){
    if(a==b && b==c) return 1;
    else return 0;
  }
  return dfs(e,i+1,a+e[i],b,c)+dfs(e,i+1,a,b+e[i],c)+dfs(e,i+1,a,b,c+e[i]);
}
int main(void){
  initialize();
  ll n,m,i,j,k,result=0;
  string s;
  
  cin >> n;
  vector<ll> e(n);
  rep(i,n) cin >> e[i];
  result = dfs(e,0,0,0,0);
  
  cout << Yes(result>=1) << endl;
  return 0;
}