#include #include #include using namespace std; template struct modint{ long long val; modint(): val(0) {} modint(long long x){ if(x < 0) val = x % MOD + MOD; else val = x % MOD; } modint(const modint &t){ val = t.val; } modint& operator =(const modint m){ val = m.val; return *this; } modint operator -(){ return modint(-val); } modint& operator-=(const modint &m){ val -= m.val; if(val < 0) val += MOD; return *this; } modint& operator+=(const modint &m){ val += m.val; if(val >= MOD) val -= MOD; return *this; } modint& operator*=(const modint &m){ val *= m.val; val %= MOD; return *this; } modint& operator/=(modint m){ *this *= m.inv(); return *this; } modint inv(){ long long x = 1, y = 0; long long a = val, b = MOD; while(b != 0){ long long t = a / b; a -= t * b; x -= t * y; swap(a, b); swap(x, y); } x %= MOD; if(x < 0) x += MOD; return modint(x); } modint pow(long long k){ long long res = 1; long long v = val; while(k > 0){ if(k & 1) res = res * v % MOD; v = v * v % MOD; k >>= 1; } return modint(res); } bool operator==(const modint &m){ return val == m.val; } modint operator+(const modint &m){ return modint(*this) += m; } modint operator-(const modint &m){ return modint(*this) -= m; } modint operator*(const modint &m){ return modint(*this) *= m; } modint operator/(const modint &m){ return modint(*this) /= m; } bool operator!=(const modint &m){ return modint(*this).val != m.val; } bool operator!=(const int &m){ return modint(*this).val != m; } }; const int MOD = 1000000007; using mint = modint; void dfs(int now, int par, vector>&G, vector>&dp){ dp[now].resize(2); dp[now][1] += 1; for(int to : G[now]){ if(to == par) continue; dfs(to, now, G, dp); vector temp(dp[now].size() + dp[to].size() - 1); for(int i = 0; i < (int)dp[now].size(); i++){ for(int j = 0; j < (int)dp[to].size(); j++){ temp[i + j] += dp[now][i] * dp[to][j]; } } dp[now] = temp; } dp[now][0] = 1; } int main(){ int N, K; cin >> N >> K; vector> G(N); for(int i = 0; i < N - 1; i++){ int a, b; cin >> a >> b; G[a].push_back(b); G[b].push_back(a); } vector> dp(N);//白が何個あるか dfs(0, -1, G, dp); cout << dp[0][N - K].val << endl; }