/*** author: yuji9511 ***/ #include // #include // using namespace atcoder; using namespace std; using ll = long long; using lpair = pair; using vll = vector; const ll MOD = 1e9+7; const ll INF = 1e18; #define rep(i,m,n) for(ll i=(m);i<(n);i++) #define rrep(i,m,n) for(ll i=(m);i>=(n);i--) ostream& operator<<(ostream& os, lpair& h){ os << "(" << h.first << ", " << h.second << ")"; return os;} #define printa(x,n) for(ll i=0;i void print(H&& h, T&&... t){cout<(t)...);} templatebool chmax(T &a, const T &b) { if (abool chmin(T &a, const T &b) { if (b> N; rep(i,2,100){ vll d = factor(i); if(d.size() == 1){ if(N % i != 0){ print(N*i); return; } }else if(d.size() == 2 && d[0] != d[1]){ vll cnt(2, 0); rep(j,0,2){ ll v = N; while(v % d[j] == 0){ cnt[j]++; v /= d[j]; } } if(cnt[0] * cnt[1] == 2){ print(N*i); return; } }else{ ll sz = d.size(); vll v2 = d; v2.erase(unique(v2.begin(), v2.end()), v2.end()); if(v2.size() == 1){ ll cnt = 0; ll v = N; while(v % v2[0] == 0){ cnt++; v /= v2[0]; } if(cnt == sz-1){ print(N*i); return; } } } } } int main(){ cin.tie(0); ios::sync_with_stdio(false); ll t; cin >> t; while(t--) solve3(); }