#include <string>
#include <vector>
#include <algorithm>
#include <numeric>
#include <set>
#include <map>
#include <queue>
#include <iostream>
#include <sstream>
#include <cstdio>
#include <cmath>
#include <ctime>
#include <cstring>
#include <cctype>
#include <cassert>
#include <limits>
#include <functional>
#define rep(i,n) for(int (i)=0;(i)<(int)(n);++(i))
#define rer(i,l,u) for(int (i)=(int)(l);(i)<=(int)(u);++(i))
#define reu(i,l,u) for(int (i)=(int)(l);(i)<(int)(u);++(i))
#if defined(_MSC_VER) || __cplusplus > 199711L
#define aut(r,v) auto r = (v)
#else
#define aut(r,v) __typeof(v) r = (v)
#endif
#define each(it,o) for(aut(it, (o).begin()); it != (o).end(); ++ it)
#define all(o) (o).begin(), (o).end()
#define pb(x) push_back(x)
#define mp(x,y) make_pair((x),(y))
#define mset(m,v) memset(m,v,sizeof(m))
#define INF 0x3f3f3f3f
#define INFL 0x3f3f3f3f3f3f3f3fLL
using namespace std;
typedef vector<int> vi; typedef pair<int, int> pii; typedef vector<pair<int, int> > vpii; typedef long long ll;
template<typename T, typename U> inline void amin(T &x, U y) { if(y < x) x = y; }
template<typename T, typename U> inline void amax(T &x, U y) { if(x < y) x = y; }

static const int dy[4] = {0, 1, 0, -1}, dx[4] = {1, 0, -1, 0};
int inity, initx, initd;
int curd, cury, curx;
vector<string> maze;

void myout(const char *s) {
	if(*s == 'R') (++ curd) %= 4;
	else if(*s == 'F') cury += dy[curd], curx += dx[curd];
	else if(*s == 'B') cury -= dy[curd], curx -= dx[curd];
	puts(s); fflush(stdout);
#ifdef MY_LOCAL_RUN
	if(maze[cury][curx] == '#') cerr << "err 1" << endl;
#endif
}

int myin() {
#ifdef MY_LOCAL_RUN
	if(maze[cury][curx] == 'G') return -1;
	return maze[cury + dy[curd]][curx + dx[curd]] == '#' ? 0 : 1;
#else
	int t = -1;
	scanf("%d", &t);
	return t;
#endif
}

set<pii> vis;
bool dfs(int i, int j, int d0) {
	if(cury != i + inity || curx != j + initx || curd != (d0 + initd) % 4) {
		cerr << "err 2" << endl;
	}
	if(vis.count(mp(i, j))) return false;
	vis.insert(mp(i, j));
	int nextds[4]; int k = 0;
	rep(di, 4) {
		int d = (d0 + di) % 4;
		int yy = i + dy[d], xx = j + dx[d];
		int t = myin();
		if(t == -1) return true;
		if(t > 0)
			nextds[k ++] = d;
		myout("R");
	}
	rep(kk, k) {
		int d = nextds[kk];
		int p = d0; 
		while(p != d) myin(), myout("R"), (++ p) %= 4;
		myin(), myout("F");
		if(dfs(i + dy[d], j + dx[d], d))
			return true;
		myin(), myout("B");
		while(p != d0) myin(), myout("R"), (++ p) %= 4;
	}
	return false;
}

int main() {
	maze = {
		"#####",
		"#...#",
		"#...G",
		"#...#"
		"#####"
	};
	inity = 1, initx = 1, initd = 0;
	cury = inity, curx = initx, curd = initd;
	bool ok = dfs(0, 0, 0);
	if(!ok) {
		cerr << "err 3" << endl;
		abort();
	}
	return 0;
}