#include <algorithm>
#include <bitset>
#include <cassert>
#include <cmath>
#include <cstdio>
#include <fstream>
#include <functional>
#include <iomanip>
#include <iostream>
#include <iterator>
#include <map>
#include <numeric>
#include <queue>
#include <set>
#include <sstream>
#include <stack>
#include <unordered_set>
using namespace std;
#if __has_include(<atcoder/all>)
#include <atcoder/all>
using namespace atcoder;
#endif
#define GET_MACRO(_1, _2, _3, NAME, ...) NAME
#define _rep(i, n) _rep2(i, 0, n)
#define _rep2(i, a, b) for(int i = (int)(a); i < (int)(b); i++)
#define rep(...) GET_MACRO(__VA_ARGS__, _rep2, _rep)(__VA_ARGS__)
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
using i64 = long long;
template<class T, class U>
bool chmin(T& a, const U& b) { return (b < a) ? (a = b, true) : false; }
template<class T, class U>
bool chmax(T& a, const U& b) { return (b > a) ? (a = b, true) : false; }

template<typename T>istream& operator>>(istream&i,vector<T>&v){rep(j,v.size())i>>v[j];return i;}
template<typename T>string join(vector<T>&v){stringstream s;rep(i,v.size())s<<' '<<v[i];return s.str().substr(1);}
template<typename T>ostream& operator<<(ostream&o,vector<T>&v){if(v.size())o<<join(v);return o;}
template<typename T>string join(vector<vector<T>>&vv){string s="\n";rep(i,vv.size())s+=join(vv[i])+"\n";return s;}
template<typename T>ostream& operator<<(ostream&o,vector<vector<T>>&vv){if(vv.size())o<<join(vv);return o;}

using mint = modint1000000007;

i64 modpow(i64 x, i64 y){
    i64 res = 1;
    while (y){
        if (y & 1){
            res *= x;
            res %= 1000000007;
        }
        x *= x;
        x %= 1000000007;
        y >>= 1;
    }
    return res;
}

int main(){
    int n;
    cin >> n;
    vector<int> a(9);
    cin >> a;
    mint ans = 0;
    mint s = 1;
    rep(i, 1, n) s *= i;
    rep(i, 9){
        if (a[i] != 0){
            s *= mint(a[i]).inv();
        }
    }
    rep(i, n){
        rep(j, 9){
            if (a[j] > 1){
                ans += s * mint(a[j] - 1).inv() * modpow(10, i) * (j + 1) * a[j];
            }
            else if (a[j] == 1){
                ans += s * modpow(10, i) * (j + 1);
            }
        }
    }
    cout << ans.val() << endl;
}