#include using namespace std; #define rep(i, n) for(int i = 0; i < int(n); i++) using ll = long long; using P = pair; // i桁まで決定されていて、数字の残りがvector aで、数字 % K == jとなるものの通り数 int main() { cin.tie(0); ios_base::sync_with_stdio(false); int n, K; cin >> n >> K; vector c(10); rep(i, 9) cin >> c[i + 1]; vector, int>, ll>> dp(n + 1); dp[0][{c, 0}] = 1; rep(i, n) { for (auto elem : dp[i]) { vector left = elem.first.first; int mod = elem.first.second; ll val = elem.second; for (int j = 1; j <= 9; j++) { if (left[j] == 0) continue; int nmod = (mod * 10 + j) % K; left[j]--; dp[i + 1][{left, nmod}] += val; left[j]++; } } } ll ans = 0; for (auto elem : dp[n]) { vector left = elem.first.first; int mod = elem.first.second; ll val = elem.second; if (mod == 0) ans += val; } cout << ans << endl; return 0; }