#include <bits/stdc++.h>
using namespace std;
typedef signed long long ll;

#define _P(...) (void)printf(__VA_ARGS__)
#define FOR(x,to) for(x=0;x<(to);x++)
#define FORR(x,arr) for(auto& x:arr)
#define FORR2(x,y,arr) for(auto& [x,y]:arr)
#define ALL(a) (a.begin()),(a.end())
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
template<class T> bool chmax(T &a, const T &b) { if(a<b){a=b;return 1;}return 0;}
template<class T> bool chmin(T &a, const T &b) { if(a>b){a=b;return 1;}return 0;}
//-------------------------------------------------------

int N;
int C[10];
map<ll,int> memo[15];
ll p10[15];

int dfs(int d,ll v) {
	if(memo[d].count(v)) return memo[d][v];
	int ret=d;
	
	if(d==N) {
		ret=0;
		while(v%2==0) {
			ret++;
			v/=2;
		}
	}
	else {
		int i;
		int D[10]={};
		ll w=v;
		FOR(i,d) D[w%10]++, w/=10;
		FOR(i,10) if(D[i]<C[i]) {
			ll v2=v+p10[d]*i;
			if(v2%(1<<(d+1))) continue;
			ret=max(ret,dfs(d+1,v2));
		}
	}
	
	
	return memo[d][v]=ret;
}

void solve() {
	int i,j,k,l,r,x,y; string s;
	
	p10[0]=1;
	FOR(i,14) p10[i+1]=p10[i]*10;
	
	cin>>N;
	FOR(i,9) {
		cin>>C[i+1];
	}
	cout<<dfs(0,0)<<endl;
}


int main(int argc,char** argv){
	string s;int i;
	if(argc==1) ios::sync_with_stdio(false), cin.tie(0);
	FOR(i,argc-1) s+=argv[i+1],s+='\n'; FOR(i,s.size()) ungetc(s[s.size()-1-i],stdin);
	cout.tie(0); solve(); return 0;
}