#include /* #include #include namespace mp = boost::multiprecision; using bint = mp::cpp_int; */ #include #include #include #include #include #include #include #include #include #include #define rep(i,n) for (int i = 0; i < int(n); ++i) #define repp(i,n,m) for (int i = m; i < int(n); ++i) #define repb(i,n) for (int i = int(n)-1; i >= 0; --i) #define fi first #define se second #define endl "\n" using namespace std; using namespace atcoder; //using namespace internal; using ll = long long; using ld = long double; using P = pair; using PL = pair; using Pxy = pair; const int INF = 1001001007; const long long mod1 = 1000000007LL; const long long mod2 = 998244353LL; const ll inf = 2e18; const ld pi = 3.14159265358979323; templatevoid priv(vector &v){if(v.size()==0){cout<void privv(vector> &v){rep(i,v.size()){rep(j,v[i].size()-1)cout<bool range(T a,T b,T x){return (a<=x&&xbool rrange(pair a,pair b,pair x){return (range(a.fi,b.fi,x.fi)&&range(a.se,b.se,x.se));} templatevoid rev(vector &v){reverse(v.begin(),v.end());} templatevoid sor(vector &v, int f=0){sort(v.begin(),v.end());if(f!=0) rev(v);} templatebool chmin(T &a,const T &b){if(a>b){a=b;return true;}return false;} templatebool chmax(T &a,const T &b){if(avoid eru(vector &v){sor(v);v.erase(unique(v.begin(),v.end()),v.end());} templateT cel(T a,T b){if (a%b==0)return a/b;return a/b +1;} template void pout(pair p){cout<void myswap(T &a,T &b){if(a>b)swap(a,b);} void yes(){cout << "Yes" << endl;} void no (){cout << "No" << endl;} void yn (bool t){if(t)yes();else no();} void Yes(){cout << "YES" << endl;} void No (){cout << "NO" << endl;} void YN (bool t){if(t)Yes();else No();} void dout() {cout << setprecision(20);} void deb(ll h = INF-1) {cout << (h == INF-1 ? "!?" : to_string(h)) << endl;} void revs(string &s) {reverse(s.begin(),s.end());} vector dx = {0,1,0,-1}; vector dy = {1,0,-1,0}; const string ALP = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"; const string alp = "abcdefghijklmnopqrstuvwxyz"; const string num = "0123456789"; ll gcds(ll a, ll b){ a = abs(a); b = abs(b); if (b == 0) return a; ll c = a % b; while (c != 0){ a = b; b = c; c = a % b; } return b; } ll tentou(vector ar){ int n = ar.size(); set st; rep(i,n) st.insert(ar[i]); map mp; int ind = 0; for (ll x : st){ mp[x] = ind; ind++; } fenwick_tree fw(ind); ll ans = 0; rep(i,n){ int a = mp[ar[i]]; ans += i - fw.sum(0,a+1); fw.add(a,1); } return ans; } /* alias g++='g++ -I/mnt/c/Users/Owner/Desktop/ac-library' */ struct vs{ vector to; vector cost; }; //頂点の2色彩色を書き足すこと struct Tree{ int n; // 頂点の数 int root; // 根付き木とみたときの根 vector par; // par[i] : 頂点 i の親 (i が根なら -1) vector edges; // edges[i] : 頂点 i から出る辺の情報 (隣接リスト) vector subtreesize; // subtreesize[i] : 頂点 i を根とする部分木のサイズ vector depth; // depth[i] : 頂点 i の深さ (i が根なら 0) vector shallow; // shallow[i] : 頂点 i が属する連結成分の最も浅い頂点の番号 int hldindex; // HLD ですでに訪れた頂点の数 vector ikigake; // ikigake[i] : 頂点 root から HLD したとき i 番目に訪れた頂点 vector pre; // 頂点 root から HLD したとき pre[i] 番目に訪れた頂点が i vector> par2; // par2[i][j] : 頂点 j から 2^i 回登った時の親 (根を通り過ぎたら -1) vector dists; // dist[i] : 頂点 root からの距離 // 根を ROOT として、par[i] (i\in [0,N)) を求める void parents(int ROOT){ par[ROOT] = -1; queue que; que.push(ROOT); while (!que.empty()){ int p = que.front(); que.pop(); for (int x : edges[p].to){ if (par[x] == -2){ par[x] = p; que.push(x); } } } } // 頂点 v を根とする部分木のサイズを求める int siz(int v){ if (subtreesize[v] != 0) return subtreesize[v]; subtreesize[v] = 1; for (int x : edges[v].to){ if (par[v] == x) continue; subtreesize[v] += siz(x); } return subtreesize[v]; } // 頂点 v の深さを求める int dep(int v){ if (depth[v] != -1) return depth[v]; if (par[v] == -1) return depth[v] = 0; return depth[v] = 1 + dep(par[v]); } // 頂点 v から HLD をする (s は v が属する連結成分の最も浅い頂点の番号) void HLD(int v, int s){ ikigake[hldindex] = v; pre[v] = hldindex; hldindex++; shallow[v] = s; int _maxsubtreesize = 0; int _index = -1; if (siz(v) == 1) return; for (int x : edges[v].to){ if (par[v] == x) continue; if (chmax(_maxsubtreesize, siz(x))){ _index = x; } } HLD(_index, s); for (int x : edges[v].to){ if (par[v] == x) continue; if (x != _index) HLD(x, x); } } // par2[i][j] を求める O(N log N) void lcainit(int N){ for (int i = 0; i < N; i++) par2[0][i] = par[i]; for (int i = 0; i < 29 ; i++) { for (int j = 0; j < N; j++) { if (par2[i][j] < 0) par2[i+1][j] = -1; else par2[i+1][j] = par2[i][par2[i][j]]; } } } // dist[i] を求める O(N) void distinit(int ROOT){ dists[ROOT] = 0; queue que; que.push(ROOT); while (!que.empty()){ int p = que.front(); que.pop(); int ind = 0; for (int x : edges[p].to){ if (dists[x] == -1) { ll addcost = 1; if (ind < edges[p].cost.size()){ addcost = edges[p].cost[ind]; } dists[x] = dists[p] + addcost; que.push(x); } ind++; } } } void init(bool hld){ parents(root); siz(root); if (hld) HLD(root,root); lcainit(n); distinit(root); } // コンストラクタ Tree (int N, vector EDGES, int ROOT = 0, bool hld = false) : n(N), edges(EDGES), root(ROOT), par(n,-2), subtreesize(n,0), depth(n,-1), shallow(n,-1), ikigake(n,-1), pre(n,-1), hldindex(0), par2(30,vector(N,-1)), dists(N,-1) { init(hld); } // u~v パスに含まれる頂点たち vector

solve(int u, int v){ vector

leftright; while (shallow[u] != shallow[v]){ if (dep(shallow[u]) <= dep(shallow[v])){ leftright.emplace_back(P(pre[shallow[v]],pre[v])); v = par[shallow[v]]; } else { leftright.emplace_back(P(pre[shallow[u]],pre[u])); u = par[shallow[u]]; } } if (pre[u] > pre[v]) swap(u,v); leftright.emplace_back(P(pre[u],pre[v])); return leftright; } // 根を root としたときの 頂点 (u,v) の最小共通祖先LCA int lca(int u, int v){ if (dep(u) > dep(v)) swap(u,v); for (int i = 0; i < 30; i++) if ((dep(v) - dep(u)) >> i & 1) v = par2[i][v]; if (u == v) return u; for (int k = 29; k >= 0; k--){ if (par2[k][u] != par2[k][v]) { u = par2[k][u]; v = par2[k][v]; } } return par2[0][u]; } ll dist(int u, int v){ int w = lca(u,v); return dists[u] + dists[v] - 2 * dists[w]; } }; int main(){ int n, q; cin >> n >> q; vector ar(n); rep(i,n-1){ int a, b; cin >> a >> b; a--; b--; ar[a].to.emplace_back(b); ar[b].to.emplace_back(a); } Tree tree(n,ar); ll ima = 0; vector ans(q); rep(i,q){ int x; cin >> x; ll v; cin >> v; ima += ll(tree.siz(x-1)) * v; ans[i] = ima; } rep(i,q) cout << ans[i] << endl; }