#include<bits/stdc++.h>
using namespace std;
#define rep(i,n) for(ll i=0;i<n;i++)
#define repl(i,l,r) for(ll i=(l);i<(r);i++)
#define per(i,n) for(ll i=(n)-1;i>=0;i--)
#define perl(i,r,l) for(ll i=r-1;i>=l;i--)
#define fi first
#define se second
#define pb push_back
#define ins insert
#define pqueue(x) priority_queue<x,vector<x>,greater<x>>
#define all(x) (x).begin(),(x).end()
#define CST(x) cout<<fixed<<setprecision(x)
#define rev(x) reverse(x);
using ll=long long;
using vl=vector<ll>;
using vvl=vector<vector<ll>>;
using pl=pair<ll,ll>;
using vpl=vector<pl>;
using vvpl=vector<vpl>;
const ll MOD=1000000007;
const ll MOD9=998244353;
const int inf=1e9+10;
const ll INF=4e18;
const ll dy[8]={1,0,-1,0,1,1,-1,-1};
const ll dx[8]={0,1,0,-1,1,-1,1,-1};
template <typename T> inline bool chmax(T &a, T b) {
  return ((a < b) ? (a = b, true) : (false));
}
template <typename T> inline bool chmin(T &a, T b) {
  return ((a > b) ? (a = b, true) : (false));
}

struct Edge{
    ll to,cost;
};
template<typename T>
struct Dijkstra{
    vector<T> dist;
    vector<int> prev;
    Dijkstra(vector<vector<Edge>> &g,int s){
        dist=vector<T>(g.size(),numeric_limits<T>::max()/5);
        prev=vector<int>(g.size(),-1);
        using pi=pair<T,int>;
        priority_queue<pi,vector<pi>,greater<pi>> que;
        dist[s]=0;
        que.emplace(dist[s],s);
        while(!que.empty()){
            T cost;int idx;
            tie(cost,idx)=que.top();que.pop();
            if(dist[idx]<cost)continue;
            for(auto &e:g[idx]){
                T ncost=cost+e.cost;
                if(dist[e.to]<=ncost)continue;
                prev[e.to]=idx;
                dist[e.to]=ncost;
                que.emplace(dist[e.to],e.to);
            }
        }
    }
    vector<int> get_path(int t){//到達できない場合、return=t;
        vector<int> path;
        for (int cur = t; cur != -1; cur = prev[cur]) {
            path.push_back(cur);
        }
        reverse(path.begin(), path.end());
        return path;
    }
};

int main(){
  ll h,w,u,d,r,l,k,p;cin >> h >> w >>u >> d>> r >> l >> k >> p;
  ll sx,sy,tx,ty;cin >> sx >> sy >> tx >> ty;sx--;sy--;tx--;ty--;
  vector<string> grid(h);rep(i,h)cin >> grid[i];
  vl cost={r,d,l,u};
  vector<vector<Edge>> g(h*w);
  rep(i,h){
    rep(j,w){
      if(grid[i][j]=='#')continue;
      ll from=i*w+j;
      rep(k,4){
        ll nx=i+dx[k],ny=j+dy[k];
        if(nx<0||nx>=h||ny<0||ny>=w)continue;
        if(grid[nx][ny]=='#')continue;
        ll to=nx*w+ny;
        ll cnt=0;if(grid[nx][ny]=='@')cnt+=p;
        g[from].push_back({to,cnt+cost[k]});
      }
    }
  }
  Dijkstra<ll> dk(g,sx*w+sy);
  //cout << dk.dist[tx*w+ty] <<endl;
  cout << (dk.dist[tx*w+ty]<=k? "Yes":"No") <<endl;
}