//code of JUYU ^ ^ never doubt youself !
#include <bits/stdc++.h>

#define For(i,a,b) for(int i=a;i<=b;i++) 
#define Rep(i,b,a) for(int i=a;i>=b;--i)
#define ms(a,b) memset(a,b,sizeof a)
#define fir first
#define sec second
#define eb emplace_back
#define pb push_back
#define mk make_pair

using namespace std;

typedef long long ll;
typedef pair<int,int> PII;

const int MOD = 1e9 + 7;
const int N = 1e5 + 10;

int ans;  //exactly you can get the answer

int main()
{
  ll k; scanf("%lld", &k);
  int ans = 0;
  for (int i1 = 1; i1 <= 8; i1 ++)
  {
    for (int i2 = 1; i2 <= 8; i2 ++)
      for (int i3 = 1; i3 <= 8; i3 ++)
        for (int i4 = 1; i4 <= 8; i4 ++)
          for (int i5 = 1; i5 <= 8; i5 ++)
            for (int i6 = 1; i6 <= 8; i6 ++)
              for (int i7 = 1; i7 <= 8; i7 ++)
                for (int i8 = 1; i8 <= 8; i8 ++)
                {
                  ll num = i1 * 10000000 + i2 * 1000000 + i3 * 100000 + i4 * 10000 + i5 * 1000 + i6 * 100 + i7 * 10 + i8;
                  if (num % k == 0 && i1 != i2 && i1 != i3 && i1 != i4 && i1 != i5 && i1 != i6 && i1 != i7 && i1 != i8 && i2 != i3 && i2 != i4 && i2 != i5 && i2 != i6 && i2 != i7 && i2 != i8 && i3 != i4 && i3 != i5 && i3 != i6 && i3 != i7 && i3 != i8 && i4 != i5 && i4 != i6 && i4 != i7 && i4 != i8 && i5 != i6 && i5 != i7 && i5 != i8 && i6 != i7 && i6 != i8 && i7 != i8) ans ++;
                }
  }
  
  cout << ans << endl;
  
  return 0;
}
/* stuff you should look for
 * int overflow, array bounds
 * special cases (n=1?)
 * do smth instead of nothing and stay organized
 * WRITE STUFF DOWN
 * DON'T GET STUCK ON ONE APPROACH
 -- Benq
*/