/** * author: ytsmash * created: 15.08.2021 10:24:54 **/ #include using namespace std; typedef long long ll; #define rep(i, n) for (int i = 0; i < (n); i++) #define all(x) x.begin(), x.end() const long double EPS = 1e-10; const long long INF = 1e18; const long double PI = acos(-1.0L); using P = pair; vector> d; vector cnt; vector B; void f(int i) { B[i] = 1; for (ll j : d[i]) { if (B[j] == 0) { f(j); cnt[i] += cnt[j]; } } return; } int main() { ll N, Q, a, b, ans = 0, p, x; cin >> N >> Q; d.resize(N); cnt.resize(N); B.resize(N); for (int i = 0; i < N - 1; i++) { cnt[i] = 1; // 頂点p[i]を根とする部分木に含まれる頂点の数 cin >> a >> b; d[a - 1].push_back(b - 1); d[b - 1].push_back(a - 1); } cnt[N - 1] = 1; f(0); rep(i, Q) { cin >> p >> x; ans += cnt[p - 1] * x; cout << ans << "\n"; } }