def sqrt(n): if n == 0: return 0 x = 1 << (n.bit_length() + 1) // 2 y = (x + n // x) // 2 while y < x: x = y y = (x + n // x) // 2 return x N = 10 ** 6 prime_list = [] # 素数リスト lpf = [0] * (N + 1) # 最小素因数 for i in range(2, N + 1): if not lpf[i]: lpf[i] = i prime_list.append(i) a = lpf[i] for p in prime_list: if p > a or p * i > N: break lpf[p*i] = p # print("lpf =", lpf) if 0: print("prime_list =", prime_list[-20:]) L, R = map(int, input().split()) # L, R = 998877, 998977 n = R - L + 1 A = [i for i in range(L, R + 1)] if 0: print("A =", A) for p in prime_list: l = ((L - 1) // p + 1) * p - L for i in range(l, n, p): if A[i] < 0: continue A[i] //= p if A[i] % p == 0: A[i] = -1 if 0: print("A =", A) ans = 0 for i in range(n): if A[i] < 0 or (A[i] > 1 and sqrt(A[i]) ** 2 == A[i]): pass else: ans += 1 if 0: print("A =", A) print(ans)