// 解法2 (愚直) #include using namespace std; static const int INF = 2e9; // Segment-Tree struct SegmentTree { int n; vector dat; SegmentTree(int _n) { init(_n); } SegmentTree(vector &a) { init((int) a.size()); for (int i = 0; i < a.size(); i++) dat[i + n - 1] = a.at(i); for (int i = n - 2; i >= 0; i--) dat[i] = min(dat[2 * i + 1], dat[2 * i + 2]); } void init(int _n) { n = 1; while (n < _n) n *= 2; dat.assign(2 * n - 1, INF); } // [a, b)の値. ノードkの範囲は[l, r) int query(int a, int b, int k = 0, int l = 0, int r = -1) { if (r == -1) r = n; if (r <= a || b <= l) return INF; if (a <= l && r <= b) return dat[k]; else { int vl = query(a, b, 2 * k + 1, l, (l + r) / 2); int vr = query(a, b, 2 * k + 2, (l + r) / 2, r); return min(vl, vr); } } }; int main() { int n, q; cin >> n >> q; vector> query(q, vector(3)); for (int i = 0; i < q; i++) { cin >> query.at(i).at(1) >> query.at(i).at(2) >> query.at(i).at(0); query.at(i).at(1)--; query.at(i).at(2)--; } sort(query.begin(), query.end()); vector a(n, 2e9); for (int i = 0; i < q; i++) { for (int j = query.at(i).at(1); j <= query.at(i).at(2); j++) { a.at(j) = query.at(i).at(0); } } SegmentTree st(a); bool ok = true; for (int i = 0; i < q; i++) { if (st.query(query.at(i).at(1), query.at(i).at(2) + 1) != query.at(i).at(0)) { ok = false; } } if (ok) { for (int i = 0; i < n; i++) { if (i) cout << " "; cout << min(st.query(i, i + 1), 1e9); } cout << '\n'; } else { cout << -1 << '\n'; } }