//code of JUYU ^ ^ never doubt youself !
#include <bits/stdc++.h>
#define For(i,j,k) for(int i=j;i<=k;++i)
#define Dow(i,j,k) for(int i=k;i>=j;--i)
#define ms(a,b) memset(a,b,sizeof a)
#define ll long long
#define pa pair<int,int>
#define fir first
#define sec second
#define eb emplace_back
#define pb push_back
#define mk make_pair

using namespace std;

const int mod = 998244353;
const int MOD = 1e9 + 7;
const int N = 1e5 + 10;

int ans;  //exactly you can get the answer

inline ll read()
{
  ll t = 0, dp = 1; char c = getchar();
  while(!isdigit(c)) {if (c == '-') dp = -1; c = getchar();}
  while(isdigit(c)) t = t * 10 + c - 48, c = getchar();
  return t * dp;
}
inline void write(ll x){if (x < 0)  {putchar('-'); x = -x;} if(x >= 10) write(x / 10); putchar(x % 10 + 48);}
inline void writeln(ll x){write(x); puts("");}
inline void write_p(ll x){write(x); putchar(' ');}

signed main()
{
  int T = read();
  
  while (T --)
  {
    int A = read(), B = read();
    
    int ans = B;
    int res = A * B;
    ans += res;
    writeln(ans);
  }
  
  return 0;
}
/* stuff you should look for
 * int overflow, array bounds
 * special cases (n=1?)
 * do smth instead of nothing and stay organized
 * WRITE STUFF DOWN
 * DON'T GET STUCK ON ONE APPROACH
 -- Benq
*/