#include <iostream>
#include <vector>
#include <cstdio>
#include <algorithm>
#include <map>
#include <set>
using namespace std;
#define rep(i,n) for(int i = 0; i < (int)(n); i++)
#define all(c) begin(c), end(c)
using ll = long long;

struct UnionFind {
    vector<int> par;
    int cnt;
    UnionFind(int size_) : par(size_, -1), cnt(size_) { }
    bool merge(int x, int y) {
        x = find(x); y = find(y);
        if (x != y) {
            if (par[y] < par[x]) swap(x, y);
            par[x] += par[y]; par[y] = x; cnt--;
        }
        return x != y;
    }
    bool get(int x, int y) { return find(x) == find(y); }
    int find(int x) { return par[x] < 0 ? x : par[x] = find(par[x]); }
    int size(int x) { return -par[find(x)]; }
    int size() { return cnt; }
};

int n, m;
vector<int> u, v;

void solve() {
    UnionFind uf(n);
    rep(i, m) {
        uf.merge(u[i] - 1, v[i] - 1);
    }
    set<int> vis; // root, size
    map<int, int> cnt;
    rep(i, n) {
        if (vis.count(uf.find(i))) continue;
        vis.insert(uf.find(i));
        cnt[uf.size(i)]++;
    }

    vector<int> size, cost;
    for (auto &p : cnt) {
        int acc = 0;
        int i = 1;
        while (i <= p.second) {
            size.push_back(p.first*i);
            cost.push_back(i);
            acc += i;
            i *= 2;
        }
        i /= 2;
        if (acc == p.second) continue;
        size.push_back(p.first * (p.second - acc));
        cost.push_back(p.second - acc);
    }
    vector<int> dp(n + 1, 1000000000);
    dp[0] = 0;
    for (int i = 0; i < cost.size(); i++) {
        for (int j = n; j >= size[i]; --j) {
            if (j - size[i] == 0) {
                dp[j] = min(dp[j], cost[i] - 1);
            }
            else {
                dp[j] = min(dp[j], dp[j - size[i]] + cost[i]);
            }
        }
    }
    for (int i = 0; i < n; i++) {
        cout << (dp[i + 1] == 1000000000 ? -1 : dp[i + 1]) << '\n';
    }
}

int main() {
    while (cin >> n >> m) {
        u.resize(m); v.resize(m);
        rep(i, m) cin >> u[i] >> v[i];
        solve();
    }
}