# 二分探索の上限をあらかじめ求めておく
lim=[0]*60
for i in range(2,60):
  lim[i]=int((10**18+10000)**(1/i))

def f(n):
  cnt=[0]*60
  for i in range(59,1,-1):
    ng,ok=lim[i]+1,0
    # floor(n^(1/i)) を二分探索で求める
    while abs(ok-ng)>1:
      mid=(ok+ng)//2
      if mid**i<=n:
        ok=mid
      else:
        ng=mid
    ok-=1
    # 約数包除
    cnt[i]=ok-sum(cnt[::i])
  return sum(cnt)+1

t=int(input())
for _ in range(t):
  k=int(input())
  ng,ok=0,10**18
  # f(n)>=k となる最小の n を二分探索で求める
  while abs(ok-ng)>1:
    mid=(ok+ng)//2
    if f(mid)>=k:
      ok=mid
    else:
      ng=mid
  print(ok)