from heapq import heappop,heappush
I=lambda:map(int,raw_input().split())
N,V,x,y=I();s=(0,0);o=(x-1,y-1);g=(N-1,N-1)
L=[I()for i in range(N)];dxy=((1,0),(0,1),(-1,0),(0,-1))
def d(s,g):
	Q=[];D=[N*[100000]for i in range(N)]
	D[s[1]][s[0]]=0
	heappush(Q,(0,s))
	while Q:
		c,h=heappop(Q)
		if h == g:break
		for dx,dy in dxy:
			nx=h[0]+dx;ny=h[1]+dy
			if 0<=nx<N and 0<=ny<N and c+L[ny][nx]<D[ny][nx]:
				D[ny][nx]=nc=c+L[ny][nx];heappush(Q,(nc,(nx,ny)))
	return D[g[1]][g[0]]
print["NO","YES"][V>d(s,g)or(o!=(-1,-1) and(V-d(s,o))*2>d(o,g))]