#include<bits/stdc++.h>
#include<unordered_map>
#define for_int(i,a,b) for(int i=(a);i<=(b);++i)
#define rep_int(i,a,b) for(int i=(a);i>=(b);--i)
#define for_ll(i,a,b) for(ll i=(a);i<=(b);++i)
#define rep_ll(i,a,b) for(ll i=(a);i>=(b);--i)
#define Ios std::ios::sync_with_stdio(false),std::cin.tie(0)
#define ull unsigned long long
#define ll long long
#define db double
#define PII std::pair<int,int>
#define PLI std::pair<long long , int>
template<class T> void chkmax(T& a, T b) { a > b ? (a = a) : (a = b); }
template<class T> void chkmin(T& a, T b) { a > b ? (a = b) : (a = a); }
template<class T> T min(T a, T b) { return a > b ? b : a; }
template<class T> T max(T a, T b) { return a < b ? b : a; }
template<class T> T abs(T a) { return a < 0 ? -a : a; }
//using namespace std;
/*
    1.注意边界情况
    2.优先考虑时间复杂度
!!! 3.求最大值时，答案应至多初始化为INT_MIN；求最小值时，答案应至少初始化为INT_MAX
    4.遇事不决先暴力
    5.代码要写简洁
    6.计数题要开long long
*/
//快速IO
template<class T>
inline bool rd(T& ret) {
    char c; int sgn;
    if (c = getchar(), c == EOF) return 0;
    while (c != '-' && (c < '0' || c > '9')) c = getchar();
    sgn = (c == '-') ? -1 : 1;
    ret = (c == '-') ? 0 : (c - '0');
    while (c = getchar(), c >= '0' && c <= '9') ret = ret * 10 + (c - '0');
    ret *= sgn;
    return true;
}
template<class T>
inline void print(T x) {
    if (x > 9) print(x / 10);
    putchar(x % 10 + '0');
    return;
}
using std::vector;
using std::queue;
using std::string;
using std::map;
using std::unordered_map;
using std::priority_queue;
using std::cout;
using std::cin;


long long n;
long long res;
int main() {
    rd(n);
    res = n;
    for (int i = 2;i <= min(n , 2000000ll) ; ++i) {
        int k = log(n) / log(i);
        long long tmp = 1, cnt = n;
        for (int j = 1; j <= k; ++j) {
            tmp *= i;
            chkmin(cnt, i + j + (n - tmp));
        }
        chkmin(res, cnt);
    }
    print(res); puts("");
    return 0;
}