#include <bits/stdc++.h>
using namespace std;
// #include <atcoder/all>
// using namespace atcoder;
#define rep(i, l, r) for (auto i = (l); i < (r); i++)
#define all(a) a.begin(), a.end()
#define chmin(dest, src) if ((dest) > (src)) dest = (src)
#define chmax(dest, src) if ((dest) < (src)) dest = (src)
using ll = long long;
using i64 = long long;
using i32 = long;
using u64 = unsigned long long;
using u32 = unsigned long;

ll pow_mod(ll a, ll e, ll m) {
  ll r = 1;
  while (e != 0) {
    if (e & 1) r = r * a % m;
    a = a * a % m;
    e >>= 1;
  }
  return r;
}

int main() {
  ll N, MOD;
  cin >> N >> MOD;

  vector<ll> fac(N + 1);
  vector<ll> finv(N + 1);
  vector<ll> inv(N + 1);
  fac[0] = fac[1] = 1;
  finv[0] = finv[1] = 1;
  inv[1] = 1;
  for (int i = 2; i <= N; i++){
      fac[i] = fac[i - 1] * i % MOD;
      inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;
      finv[i] = finv[i - 1] * inv[i] % MOD;
  }

  auto comb = [&](ll n, ll k) -> ll {
    if (n < k) return 0;
    if (n < 0 || k < 0) return 0;
    return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;
  };

  // http://oeis.org/A105599
  // T[n][m] = n頂点でm本の木を作る場合の数
  vector<vector<ll>> T(N + 1, vector<ll>(N + 1, 0));
  T[0][0] = 1;
  rep (n, 1, N + 1) {
    rep (m, 1, n + 1) {
      rep (k, 1, n - m + 2) {
        if (k >= 2) {
          T[n][m] += comb(n - 1, k - 1) * pow_mod(k, k - 2, MOD) % MOD * T[n - k][m - 1] % MOD;
          T[n][m] %= MOD;
        } else {
          T[n][m] += T[n - k][m - 1];
          T[n][m] %= MOD;
        }
      }
    }
  }

  rep (m, 0, N) {
    if (T[N][N - m] < 0) T[N][N - m] += MOD;
    cout << T[N][N - m] % MOD << "\n";
  }

  return 0;
}