#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; #define REP(i,a,b) for(int i=a;i<(int)b;i++) #define rep(i,n) REP(i,0,n) #define all(c) (c).begin(), (c).end() #define zero(a) memset(a, 0, sizeof a) #define minus(a) memset(a, -1, sizeof a) template inline bool minimize(T1 &a, T2 b) { return b < a && (a = b, 1); } template inline bool maximize(T1 &a, T2 b) { return a < b && (a = b, 1); } typedef long long ll; int const inf = 1<<29; int main() { int N; cin >> N; int S[N]; rep(i, N) cin >> S[i]; int M; cin >> M; int dp[N][N]; rep(i, N) rep(j, N) if(i==j) dp[i][i] = 0; else dp[i][j] = inf; rep(i, M) { int a, b, c; cin >> a >> b >> c; dp[a][b] = dp[b][a] = c; } rep(k, N) rep(i, N) rep(j, N) { if(dp[i][k] == inf || dp[k][j] == inf) continue; if(dp[i][j] > dp[i][k] + dp[k][j]) { dp[i][j] = dp[i][k] + dp[k][j]; } } int ans = inf; REP(i, 1, N-1) REP(j, 1, N-1) { if(i == j) continue; minimize(ans, dp[0][i] + dp[i][j] + dp[j][N-1] + S[i] + S[j]); } cout << ans << endl; return 0; }