#define MOD_TYPE 1 #pragma region Macros #include using namespace std; #include using namespace atcoder; #if 0 #include #include using Int = boost::multiprecision::cpp_int; using lld = boost::multiprecision::cpp_dec_float_100; #endif #if 1 #pragma GCC target("avx2") #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") #endif using ll = long long int; using ld = long double; using pii = pair; using pll = pair; using pld = pair; template using smaller_queue = priority_queue, greater>; #if MOD_TYPE == 1 constexpr ll MOD = ll(1e9 + 7); #else #if MOD_TYPE == 2 constexpr ll MOD = 998244353; #else constexpr ll MOD = 1000003; #endif #endif using mint = static_modint; constexpr int INF = (int)1e9 + 10; constexpr ll LINF = (ll)4e18; constexpr double PI = acos(-1.0); constexpr double EPS = 1e-11; constexpr int Dx[] = {0, 0, -1, 1, -1, 1, -1, 1, 0}; constexpr int Dy[] = {1, -1, 0, 0, -1, -1, 1, 1, 0}; #define REP(i, m, n) for (ll i = m; i < (ll)(n); ++i) #define rep(i, n) REP(i, 0, n) #define REPI(i, m, n) for (int i = m; i < (int)(n); ++i) #define repi(i, n) REPI(i, 0, n) #define MP make_pair #define MT make_tuple #define YES(n) cout << ((n) ? "YES" : "NO") << "\n" #define Yes(n) cout << ((n) ? "Yes" : "No") << "\n" #define possible(n) cout << ((n) ? "possible" : "impossible") << "\n" #define Possible(n) cout << ((n) ? "Possible" : "Impossible") << "\n" #define Yay(n) cout << ((n) ? "Yay!" : ":(") << "\n" #define all(v) v.begin(), v.end() #define NP(v) next_permutation(all(v)) #define dbg(x) cerr << #x << ":" << x << "\n"; #define UNIQUE(v) v.erase(unique(all(v)), v.end()) struct io_init { io_init() { cin.tie(nullptr); ios::sync_with_stdio(false); cout << setprecision(30) << setiosflags(ios::fixed); }; } io_init; template inline bool chmin(T &a, T b) { if (a > b) { a = b; return true; } return false; } template inline bool chmax(T &a, T b) { if (a < b) { a = b; return true; } return false; } inline ll CEIL(ll a, ll b) { return (a + b - 1) / b; } template inline void Fill(A (&array)[N], const T &val) { fill((T *)array, (T *)(array + N), val); } template vector compress(vector &v) { vector val = v; sort(all(val)), val.erase(unique(all(val)), val.end()); for (auto &&vi : v) vi = lower_bound(all(val), vi) - val.begin(); return val; } template constexpr istream &operator>>(istream &is, pair &p) noexcept { is >> p.first >> p.second; return is; } template constexpr ostream &operator<<(ostream &os, pair p) noexcept { os << p.first << " " << p.second; return os; } ostream &operator<<(ostream &os, mint m) { os << m.val(); return os; } random_device seed_gen; mt19937_64 engine(seed_gen()); struct BiCoef { vector fact_, inv_, finv_; BiCoef(int n) noexcept : fact_(n, 1), inv_(n, 1), finv_(n, 1) { fact_.assign(n, 1), inv_.assign(n, 1), finv_.assign(n, 1); for (int i = 2; i < n; i++) { fact_[i] = fact_[i - 1] * i; inv_[i] = -inv_[MOD % i] * (MOD / i); finv_[i] = finv_[i - 1] * inv_[i]; } } mint C(ll n, ll k) const noexcept { if (n < k || n < 0 || k < 0) return 0; return fact_[n] * finv_[k] * finv_[n - k]; } mint P(ll n, ll k) const noexcept { return C(n, k) * fact_[k]; } mint H(ll n, ll k) const noexcept { return C(n + k - 1, k); } mint Ch1(ll n, ll k) const noexcept { if (n < 0 || k < 0) return 0; mint res = 0; for (int i = 0; i < n; i++) res += C(n, i) * mint(n - i).pow(k) * (i & 1 ? -1 : 1); return res; } mint fact(ll n) const noexcept { if (n < 0) return 0; return fact_[n]; } mint inv(ll n) const noexcept { if (n < 0) return 0; return inv_[n]; } mint finv(ll n) const noexcept { if (n < 0) return 0; return finv_[n]; } }; BiCoef bc(500010); #pragma endregion template struct Tree { int V; using P = pair; vector> E; vector par, depth, in, out; vector dist; vector> par_double; Tree() {} Tree(int V) : V(V) { E.resize(V); depth.resize(V); dist.resize(V); in.resize(V); out.resize(V); } void read(int index = 1, bool ini = true) { int a, b; for (int i = 0; i < V - 1; i++) { cin >> a >> b, a -= index, b -= index; E[a].push_back({b, 1}); E[b].push_back({a, 1}); } if (ini) init(); } void add_edge(int a, int b, T w = 1) { E[a].push_back({b, w}); E[b].push_back({a, w}); } void dfs(int v, int d, T w, int &i) { in[v] = i++; depth[v] = d; dist[v] = w; for (auto [c, di] : E[v]) { if (par[v] == c) continue; par[c] = v; dfs(c, d + 1, w + di, i); } out[v] = i; } inline int sub(int v) { return out[v] - in[v]; } void init(int root = 0) { calculated = false; par.assign(V, -1); int i = 0; dfs(root, 0, 0, i); } bool calculated; void calc_double() { par_double.assign(V, vector(25)); for (int i = 0; i < V; i++) par_double[i][0] = par[i]; for (int k = 0; k < 24; k++) { for (int i = 0; i < V; i++) { if (par_double[i][k] == -1) par_double[i][k + 1] = -1; else par_double[i][k + 1] = par_double[par_double[i][k]][k]; } } } int getLCA(int a, int b) { if (!calculated) calc_double(), calculated = true; if (a == b) return a; if (depth[a] < depth[b]) swap(a, b); for (int k = 24; k >= 0; k--) { if (par_double[a][k] != -1 && depth[par_double[a][k]] >= depth[b]) a = par_double[a][k]; } if (a == b) return a; for (int k = 24; k >= 0; k--) { if (par_double[a][k] != -1 && par_double[a][k] != par_double[b][k]) { a = par_double[a][k]; b = par_double[b][k]; } } return par_double[a][0]; } int length(int a, int b) { return depth[a] + depth[b] - 2 * depth[getLCA(a, b)]; } T distance(int a, int b) { return dist[a] + dist[b] - 2 * dist[getLCA(a, b)]; } T diameter(int &a, int &b) { T Max(-1), d; for (int i = 0; i < V; i++) { d = distance(0, i); if (Max < d) Max = d, a = i; } Max = -1; for (int i = 0; i < V; i++) { d = distance(a, i); if (Max < d) Max = d, b = i; } return Max; } T diameter() { int a, b; return diameter(a, b); } int unweighted_diameter(int &a, int &b) { int Max = -1, d; for (int i = 0; i < V; i++) { d = length(0, i); if (Max < d) Max = d, a = i; } Max = -1; for (int i = 0; i < V; i++) { d = length(a, i); if (Max < d) Max = d, b = i; } return Max; } int unweighted_diameter() { int a, b; return unweighted_diameter(a, b); } }; void solve() { int n; cin >> n; Tree tr(n); rep(i, n - 1) { int a, b, c; cin >> a >> b >> c; a--, b--; tr.add_edge(a, b, c); } tr.init(); int q; cin >> q; rep(i, q) { int s, t; cin >> s >> t; s--, t--; cout << tr.distance(s, t) << "\n"; } } int main() { solve(); }