class UnionFind: def __init__(self, n): self.parent = [-1] * n self.n = n self.cnt = n def root(self, x): if self.parent[x] < 0: return x else: self.parent[x] = self.root(self.parent[x]) return self.parent[x] def merge(self, x, y): x = self.root(x) y = self.root(y) if x == y: return False if self.parent[x] > self.parent[y]: x, y = y, x self.parent[x] += self.parent[y] self.parent[y] = x self.cnt -= 1 return True def same(self, x, y): return self.root(x) == self.root(y) def size(self, x): return -self.parent[self.root(x)] def count(self): return self.cnt def groups(self): res = [[] for _ in range(self.n)] for i in range(self.n): res[self.root(i)].append(i) return [group for group in res if group] def is_eulerian(digraph): n = len(digraph) diffs = [0] * n # diff = outdeg - indeg uf = UnionFind(n) vs = set([]) for v in range(n): for nxt_v in digraph[v]: diffs[v] += 1 diffs[nxt_v] -= 1 uf.merge(v, nxt_v) vs.add(v) vs.add(nxt_v) if len(vs) - n + uf.count() != 1: # 非連結な路が存在するので有向オイラー路が存在しない return False, -1, -1 if diffs.count(0) == n: # 有向オイラー閉路 return True, -1, -1 s, t = [], [] for v, diff in enumerate(diffs): if diff == 1: s.append(v) if diff == -1: t.append(v) if len(s) == 1 and len(t) == 1: # 始点 s[0], 終点 t[0] の有向オイラー路 return True, s[0], t[0] else: # 有向オイラー路が存在しない return False, -1, -1 n, m = map(int, input().split()) graph = [[] for _ in range(n)] for _ in range(m): a, b = map(int, input().split()) graph[a].append(b) graph[b].append(a) judge, s, t = is_eulerian(graph) if judge and s == -1 and t == -1: print("YES") else: print("NO")