#include using namespace std; #define rep(i,n) for(ll i=0;i=0;i--) #define perl(i,r,l) for(ll i=r-1;i>=l;i--) #define fi first #define se second #define pb push_back #define ins insert #define pqueue(x) priority_queue,greater> #define all(x) (x).begin(),(x).end() #define CST(x) cout<; using vvl=vector>; using pl=pair; using vpl=vector; using vvpl=vector; const ll MOD=1000000007; const ll MOD9=998244353; const int inf=2e9+1; const ll INF=4e18; const ll dy[8]={-1,0,1,0,1,1,-1,-1}; const ll dx[8]={0,-1,0,1,1,-1,1,-1}; template inline bool chmax(T &a, T b) { return ((a < b) ? (a = b, true) : (false)); } template inline bool chmin(T &a, T b) { return ((a > b) ? (a = b, true) : (false)); } ll mod=1000;//一次元ベクトルの高速化dp vl matmul(vl &dp, vvl &mt){ ll m=dp.size(); vl ret(m,0); rep(i,m)rep(j,m){ ret[i]+=mt[i][j]*dp[j]; ret[i]%=mod; } return ret; } vvl update(vvl &mt){ ll m=mt.size(); vvl ret(m,vl(m,0)); rep(i,m)rep(j,m)rep(k,m){ ret[i][j]+=mt[i][k]*mt[k][j]; ret[i][j]%=mod; } return ret; } void matpow(vl &dp, vvl &mt, ll k){ ll m=dp.size(); while(k){ if(k&1)dp=matmul(dp,mt); mt=update(mt); k/=2; } } int main(){ ll n;cin >> n; vvl mat(2,vl(2,1));mat[0][1]=3; vl dp={1,0}; matpow(dp,mat,n); //cout << dp[0] << endl; ll ans=dp[0]; ans*=2; if(n%2==0)ans--; cout << (ans+mod)%mod << endl; }