#[allow(unused_imports)] use std::cmp::*; #[allow(unused_imports)] use std::collections::*; use std::io::Read; fn get_word() -> String { let stdin = std::io::stdin(); let mut stdin=stdin.lock(); let mut u8b: [u8; 1] = [0]; loop { let mut buf: Vec = Vec::with_capacity(16); loop { let res = stdin.read(&mut u8b); if res.unwrap_or(0) == 0 || u8b[0] <= b' ' { break; } else { buf.push(u8b[0]); } } if buf.len() >= 1 { let ret = String::from_utf8(buf).unwrap(); return ret; } } } #[allow(dead_code)] fn get() -> T { get_word().parse().ok().unwrap() } /** * Segment Tree. This data structure is useful for fast folding on intervals of an array * whose elements are elements of monoid I. Note that constructing this tree requires the identity * element of I and the operation of I. * Verified by: yukicoder No. 259 (http://yukicoder.me/submissions/100581) * AGC015-E (http://agc015.contest.atcoder.jp/submissions/1461001) */ struct SegTree { n: usize, dat: Vec, op: BiOp, e: I, } impl SegTree where BiOp: Fn(I, I) -> I, I: Copy { pub fn new(n_: usize, op: BiOp, e: I) -> Self { let mut n = 1; while n < n_ { n *= 2; } // n is a power of 2 SegTree {n: n, dat: vec![e; 2 * n - 1], op: op, e: e} } /* ary[k] <- v */ pub fn update(&mut self, idx: usize, v: I) { let mut k = idx + self.n - 1; self.dat[k] = v; while k > 0 { k = (k - 1) / 2; self.dat[k] = (self.op)(self.dat[2 * k + 1], self.dat[2 * k + 2]); } } /* [a, b) (note: half-inclusive) * http://proc-cpuinfo.fixstars.com/2017/07/optimize-segment-tree/ */ pub fn query(&self, mut a: usize, mut b: usize) -> I { let mut left = self.e; let mut right = self.e; a += self.n - 1; b += self.n - 1; while a < b { if (a & 1) == 0 { left = (self.op)(left, self.dat[a]); } if (b & 1) == 0 { right = (self.op)(self.dat[b - 1], right); } a = a / 2; b = (b - 1) / 2; } (self.op)(left, right) } } fn main() { let n: usize = get(); let q: usize = get(); let a: Vec = (0..n).map(|_| get()).collect(); let mut sts = SegTree::new(n, |x, y| x + y, 0i64); let mut stc = SegTree::new(n, |x, y| x + y, 0i64); let mut ev = vec![]; let mut ans = vec![0; q]; for i in 0..q { let ty: i32 = get(); assert_eq!(ty, 1); let l = get::() - 1; let r: usize = get(); let x: i64 = get(); ev.push((x, l, r, 1 + i)); } for i in 0..n { ev.push((a[i], i, i + 1, 0)); } ev.sort(); ev.reverse(); for (x, l, r, ty) in ev { if ty == 0 { sts.update(l, a[l]); stc.update(l, 1); } else { ans[ty - 1] = sts.query(l, r) - x * stc.query(l, r); } } for i in 0..q { println!("{}", ans[i]); } }