#include using namespace std; const int N = 2e5 + 10, mod = 1e9 + 7; typedef long long ll; ll dp[N],a[N]; int n; ll work(int i) { ll sum = 0; sum += ((dp[i - 2] + mod) % mod + ((a[i - 1] % mod * a[i] % mod) % mod)) % mod; sum += ((dp[i - 2] + mod) % mod - ((a[i - 1] % mod * a[i] % mod) % mod)) % mod; sum += (((dp[i - 2] + mod) % mod) * ((a[i - 1] % mod * a[i] % mod) % mod)) % mod; return sum; } int main() { scanf("%d",&n); for(int i = 0;i < n;i ++ ) scanf("%lld",&a[i]); dp[0] = a[0]; for(int i = 1;i < n;i ++ ) { if(i == 1) { dp[i] = ((dp[i - 1] % mod + a[i] % mod) % mod + ((dp[i - 1] % mod) - (a[i] % mod) + mod) % mod + (dp[i - 1] % mod * a[i] % mod) % mod) % mod; } else { dp[i] = ((dp[i - 1] % mod + a[i] % mod) % mod + ((dp[i - 1] % mod) - (a[i] % mod) + mod) % mod + work(i) % mod) % mod; } } printf("%lld\n",dp[n - 1]); return 0; }