#include #include using namespace std; using namespace atcoder; using mint = modint998244353; //using mint = modint1000000007; using ll = long long; using ld = long double; using pll = pair; using tlll = tuple; constexpr ll INF = 1LL << 60; template bool chmin(T& a, T b) {if (a > b) {a = b; return true;} return false;} template bool chmax(T& a, T b) {if (a < b) {a = b; return true;} return false;} ll safemod(ll A, ll M) {return (A % M + M) % M;} ll divfloor(ll A, ll B) {if (B < 0) {return divfloor(-A, -B);} return (A - safemod(A, B)) / B;} ll divceil(ll A, ll B) {if (B < 0) {return divceil(-A, -B);} return divfloor(A + B - 1, B);} #define FINALANS(A) do {cout << (A) << '\n'; exit(0);} while (false) int main() { ll N; cin >> N; vector B(N, 0); for (ll i = 0; i < N; i++) { ll K; cin >> K; for (ll j = 0; j < K; j++) { ll C; cin >> C; C--; B.at(i) |= (1LL << C); } } const ll M = 12; vector> dp(N + 1, vector((1LL << M), 0)); dp.at(0).at((1LL << M) - 1) = 1; for (ll i = 0; i < N; i++) { for (ll b = 0; b < (1LL << M); b++) { ll nb = b & B.at(i); dp.at(i + 1).at(nb) += dp.at(i).at(b); dp.at(i + 1).at(b) += dp.at(i).at(b); } } ll ans = dp.at(N).at(0).val(); cout << ans << endl; }