import sys
from operator import itemgetter
from collections import defaultdict, deque
import heapq
import bisect
from itertools import combinations, product

stdin=sys.stdin
sys.setrecursionlimit(10 ** 8)

ip=lambda: int(sp())
fp=lambda: float(sp())
lp=lambda:list(map(int,stdin.readline().split()))
sp=lambda:stdin.readline().rstrip()
Yp=lambda:print('Yes')
Np=lambda:print('No')
inf = float('inf')
eps = 1e-9
sortkey = itemgetter(0)

from collections import Counter

class union_find():
    def __init__(self,n):
        self.n=n
        ##親要素のノード番号を格納。par[x]==xのときそのノードは根
        ##親とはその上にノードなし！！　
        self.par=[-1 for i in range(n)]
        self.rank=[0]*(n)

    def find(self,x):
        if self.par[x]<0:
            return x
        else:
            self.par[x]=self.find(self.par[x])
            
            return self.par[x]

    def union(self,x,y):
        x=self.find(x)
        y=self.find(y)

        ##木の高さを比較し、低い方から高い方へ辺をはる
        if x==y:
          return

        if self.par[x]>self.par[y]:
          x,y=y,x
          
        self.par[x]+=self.par[y]
        self.par[y]=x

    ##２つが同じ親かどうか
    def same(self,x,y):
        return self.find(x) == self.find(y)
    
    ##所属のサイズ
    def size(self,x):
      return -self.par[self.find(x)]
      
    ##同じ親のものを表示
    def members(self,x):
      root=self.find(x)
      return [i for i in range(self.n) if self.find(i)==root]
    
    ##親を表示！！
    def roots(self):
      return [i for i, x in enumerate(self.par) if x<0]
    
    def all_group_member(self):
      return {r:self.members(r) for r in self.roots()}

    def group_count(self):
      return len(self.roots())

## uf memo
## 素集合に分けるが、各集合には親というIDが振られているという意識を持つ！！（ABC049_Dより）

###############################################################

N, M, K = lp()
A = lp()
edges = [[inf for _ in range(N)] for _ in range(N)]
for i in range(N):
    edges[i][i] = 0

for _ in range(M):
    x, y, z = lp()
    x -= 1; y -= 1
    edges[x][y] = z
    edges[y][x] = z

for mid in range(N):
    for s in range(N):
        for g in range(N):
            dist = min(edges[s][g], edges[s][mid] + edges[mid][g])
            edges[s][g] = dist

adj = [[edges[i][j], i, j]for i, j in product(range(N), repeat=2) if i < j]
adj.sort(key=lambda x:x[0])


citys = [i for i in range(N)]
ans = inf
for v in combinations(citys,K):
    uf = union_find(N)
    temp = 0
    candidate = [0 for _ in range(N)]
    cnt = 0
    for city in v:
        temp += A[city]
        candidate[city] = 1
    if cnt == K - 1:
        ans = min(ans, temp)
        continue

    for cost, x, y in adj:
        if candidate[x] == 1 and candidate[y] == 1 and not uf.same(x, y):
            uf.union(x, y)
            temp += cost
            cnt += 1

        if cnt == K - 1:
            ans = min(ans, temp)
            break

print(ans)