#include #include #include #include #include #include #include #include #include #include #include #include #define pb push_back #define rep(i, n) for (int i = 0; i < (n); i++) #define reps(i, n, s) for (int i = (s); i < (n); i++) #define rrep(i, n) for (int i = (n - 1); i >= 0; i--) #define rreps(i, n, s) for (int i = s; i >= n; i--) using ll = long long; using namespace std; constexpr long long MAX = 5100000; constexpr long long INF = 1LL << 60; constexpr int MOD = 1000000007; class mint { public: long long x; mint(long long x = 0) : x((x % MOD + MOD) % MOD) {} mint operator-() const { return mint(-x); } mint& operator+=(const mint& a) { if ((x += a.x) >= MOD) x -= MOD; return *this; } mint& operator-=(const mint& a) { if ((x += MOD - a.x) >= MOD) x -= MOD; return *this; } mint& operator*=(const mint& a) { (x *= a.x) %= MOD; return *this; } mint operator+(const mint& a) const { mint res(*this); return res += a; } mint operator-(const mint& a) const { mint res(*this); return res -= a; } mint operator*(const mint& a) const { mint res(*this); return res *= a; } mint pow(ll t) const { if (!t) return 1; mint a = pow(t >> 1); a *= a; if (t & 1) a *= *this; return a; } // for prime MOD mint inv() const { return pow(MOD - 2); } mint& operator/=(const mint& a) { return (*this) *= a.inv(); } mint operator/(const mint& a) const { mint res(*this); return res /= a; } friend ostream& operator<<(ostream& os, const mint& m) { os << m.x; return os; } }; int main() { cin.tie(0); ios::sync_with_stdio(false); ll a, b; cin >> a >> b; if (a < b) swap(a, b); mint x1 = ceil((long double)(-a - b) / 2.0); mint x2l = floor((long double)(b - a) / 2.0); x2l.x = max(x1.x, x2l.x); mint x2r = ceil((long double)(b - a) / 2.0); mint x3l = floor((long double)(a - b) / 2.0); mint x3r = ceil((long double)(a - b) / 2.0); mint x4 = floor((long double)(a + b) / 2.0); x3r.x = min(x3r.x, x4.x); mint dy1 = ((x1 + b) - (-x1 - a) + 1LL); mint dy2l = ((x2l + b) - (-x2l - a) + 1LL); mint dy2r3l = ((x2r + b) - (x2r - b) + 1LL); mint dy3r = ((-x3r + a) - (x3l - b) + 1LL); mint dy4 = ((-x4 + a) - (x4 - b) + 1LL); mint res = 0; res += (x2l - x1 + 1LL) * (dy1 + dy2l) / 2.0; res += (x3l - x2r + 1LL) * dy2r3l; res += (x4 - x3r + 1LL) * (dy3r + dy4) / 2.0; if (x2l.x == x2r.x) res -= dy2l; if (x3l.x == x3r.x) res -= dy3r; cout << res << endl; return 0; }