// 想定解 C++

#include <bits/stdc++.h>

using namespace std;

int main() {
    int H, W;
    int ni, nj;
    int zi, zj;
    
    cin >> H >> W;
    cin >> ni >> nj;
    cin >> zi >> zj;
    
    if ((abs(ni - zi) + abs(nj - zj)) % 2 == 1) {
        cout << "Yes" << endl;
    } else {
        cout << "No" << endl;
    }
    
    return 0;
}