#include<bits/stdc++.h>
using namespace std;
#define rep(i,n) for(ll i=0;i<n;i++)
#define repl(i,l,r) for(ll i=(l);i<(r);i++)
#define per(i,n) for(ll i=(n)-1;i>=0;i--)
#define perl(i,r,l) for(ll i=r-1;i>=l;i--)
#define fi first
#define se second
#define pb push_back
#define ins insert
#define pqueue(x) priority_queue<x,vector<x>,greater<x>>
#define all(x) (x).begin(),(x).end()
#define CST(x) cout<<fixed<<setprecision(x)
#define rev(x) reverse(x);
using ll=long long;
using vl=vector<ll>;
using vvl=vector<vector<ll>>;
using pl=pair<ll,ll>;
using vpl=vector<pl>;
using vvpl=vector<vpl>;
const ll MOD=1000000007;
const ll MOD9=998244353;
const int inf=2e9+1;
const ll INF=4e18;
const ll dy[8]={-1,0,1,0,1,1,-1,-1};
const ll dx[8]={0,-1,0,1,1,-1,1,-1};
template <typename T> inline bool chmax(T &a, T b) {
  return ((a < b) ? (a = b, true) : (false));
}
template <typename T> inline bool chmin(T &a, T b) {
  return ((a > b) ? (a = b, true) : (false));
}


const int mod = MOD;
const int max_n = 200005;
struct mint {
  ll x; // typedef long long ll;
  mint(ll x=0):x((x%mod+mod)%mod){}
  mint operator-() const { return mint(-x);}
  mint& operator+=(const mint a) {
    if ((x += a.x) >= mod) x -= mod;
    return *this;
  }
  mint& operator-=(const mint a) {
    if ((x += mod-a.x) >= mod) x -= mod;
    return *this;
  }
  mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;}
  mint operator+(const mint a) const { return mint(*this) += a;}
  mint operator-(const mint a) const { return mint(*this) -= a;}
  mint operator*(const mint a) const { return mint(*this) *= a;}
  mint pow(ll t) const {
    if (!t) return 1;
    mint a = pow(t>>1);
    a *= a;
    if (t&1) a *= *this;
    return a;
  }
  bool operator==(const mint &p) const { return x == p.x; }
  bool operator!=(const mint &p) const { return x != p.x; }
  // for prime mod
  mint inv() const { return pow(mod-2);}
  mint& operator/=(const mint a) { return *this *= a.inv();}
  mint operator/(const mint a) const { return mint(*this) /= a;}
};
istream& operator>>(istream& is, mint& a) { return is >> a.x;}
ostream& operator<<(ostream& os, const mint& a) { return os << a.x;}
using vm=vector<mint>;
using vvm=vector<vm>;

// fast Walsh–Hadamard transform
template<class T>
std::vector<T> fast_hadamard_transform(std::vector<T> vec) {
    using hadamard_size_type = typename std::vector<T>::size_type;

    auto vec_size = vec.size();

    // check vec_size is power of 2
    assert(((vec_size - 1)&vec_size) == 0);
    
    for(hadamard_size_type i = 1; i < vec_size; i = i << 1) {
        auto mask = ~i;
        for(auto j = i; j < vec_size; j = (j+1)|i) {
            T a = vec[j&mask];
            T &b = vec[j];
            vec[j&mask] += b;
            b = a - b;
        }
    }

    return vec;
}

mint ivs=mint(1)/(1<<10);
// inverse fast Walsh–Hadamard transform
template<class VecType>
auto inv_fast_hadamard_transform (VecType &&vec) {
    auto vec_size = vec.size();
    auto &&ret = fast_hadamard_transform(std::forward<VecType>(vec));
    for(auto &i : ret) i *=ivs;
    return ret;
}

// bitwise xor convolution
// using fast-Walsh–Hadamard-transform
template<class T>
std::vector<T> xor_convolution
    (const std::vector<T> &a, const std::vector<T> &b) {
    using xorconv_size_type = typename std::vector<T>::size_type;

    assert(a.size() == b.size());

    auto vec_size = a.size();
    std::vector<T> &&transa = fast_hadamard_transform(a),
                   &&transb = fast_hadamard_transform(b);
    
    for(xorconv_size_type i = 0; i < vec_size; i++) {
        transa[i] *= transb[i];
    }
    return inv_fast_hadamard_transform(transa);
}

vm comp(ll n){
    vm va(1<<10);
    ll now=0;va[0]=1;
    rep(i,n){
      ll a;cin >> a;now^=a;va[now]+=1;
    }
    vm ca=fast_hadamard_transform(va);
    mint invtwo=mint(1)/2;
    rep(i,1<<10){
      ca[i]*=ca[i];
      ca[i]-=n+1;
      ca[i]*=invtwo;
    }
    return ca;
}
int main(){
    ll n,m,k;cin >> n >> m >> k;
    auto p=comp(n);
    auto q=comp(m);
    rep(i,1<<10)p[i]*=q[i];
    auto r=inv_fast_hadamard_transform(p);
    cout << r[k] << endl;
}