#define _USE_MATH_DEFINES #include using namespace std; #define FOR(i,m,n) for(int i=(m);i<(n);++i) #define REP(i,n) FOR(i,0,n) #define ALL(v) (v).begin(),(v).end() using ll = long long; constexpr int INF = 0x3f3f3f3f; constexpr long long LINF = 0x3f3f3f3f3f3f3f3fLL; constexpr double EPS = 1e-8; constexpr int MOD = 1000000007; // constexpr int MOD = 998244353; constexpr int DY[]{1, 0, -1, 0}, DX[]{0, -1, 0, 1}; constexpr int DY8[]{1, 1, 0, -1, -1, -1, 0, 1}, DX8[]{0, -1, -1, -1, 0, 1, 1, 1}; template inline bool chmax(T &a, U b) { return a < b ? (a = b, true) : false; } template inline bool chmin(T &a, U b) { return a > b ? (a = b, true) : false; } struct IOSetup { IOSetup() { std::cin.tie(nullptr); std::ios_base::sync_with_stdio(false); std::cout << fixed << setprecision(20); } } iosetup; template std::vector longest_increasing_subsequence(const std::vector &a, bool is_strict = true) { const T inf = std::numeric_limits::max(); const int n = a.size(); std::vector idx(n); std::vector tmp(n, inf); for (int i = 0; i < n; ++i) { if (is_strict) { idx[i] = std::distance(tmp.begin(), std::lower_bound(tmp.begin(), tmp.end(), a[i])); } else { idx[i] = std::distance(tmp.begin(), std::upper_bound(tmp.begin(), tmp.end(), a[i])); } tmp[idx[i]] = a[i]; } int res_size = std::distance(tmp.begin(), std::lower_bound(tmp.begin(), tmp.end(), inf)); std::vector res(res_size--); for (int i = n - 1; res_size >= 0 && i >= 0; --i) { if (idx[i] == res_size) { res[res_size--] = a[i]; } } return res; } int main() { int n, m, q; cin >> n >> m >> q; vector> ab(q); REP(i, q) cin >> ab[i].first >> ab[i].second; sort(ALL(ab), [](const pair &l, const pair &r) -> bool { return l.first != r.first ? l.first < r.first : l.second > r.second; }); vector b(q); REP(i, q) b[i] = ab[i].second; cout << longest_increasing_subsequence(b).size() << '\n'; return 0; }