#include<iostream>
using namespace std;
int main(void)
{
	int n, i,marua=0,marub=0,batu=0;
	char sa[3], sb[3];


	cin >> sa >> n >> sb;

	for (i = 0; i < 3; i++) {
		if (sa[i] == 'o')marua++;
		if (sb[i] == 'o')marub++;
	}
	if (marua != marub) {
		cout << "SUCCESS" << endl;
		return 0;
	}

	if (n > 1||marua==3||marub==0) {
		cout << "FAILURE" << endl;
	}
	else {
		if (n == 0 && sa[0] == sb[0] && sa[1] == sb[1])//n0で一緒
			cout << "FAILURE" << endl;
		else if ((n == 1 && sa[0] == sa[2] && sa[1] != sb[1]) || (n == 1 && sa[0] != sa[2] &&( (sa[1] != sb[1])||(sa[0]==sb[0]&&sa[1]==sb[1]))))//n1であり得る組み合わせ
			cout << "FAILURE" << endl;
		else
			cout << "SUCCESS" << endl;

	}



	return 0;
}