#include using namespace std; #define rep(i,n) for(ll i=0;i=0;i--) #define perl(i,r,l) for(ll i=r-1;i>=l;i--) #define fi first #define se second #define pb push_back #define ins insert #define pqueue(x) priority_queue,greater> #define all(x) (x).begin(),(x).end() #define CST(x) cout<> #define rev(x) reverse(x); using ll=long long; using vl=vector; using vvl=vector>; using pl=pair; using vpl=vector; using vvpl=vector; const ll MOD=1000000007; const ll MOD9=998244353; const int inf=1e9+10; const ll INF=4e18; const ll dy[9]={0,1,-1,0,1,1,-1,-1,0}; const ll dx[9]={1,0,0,-1,1,-1,1,-1,0}; template inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; } template inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; } ll mod=1000000007;//一次元ベクトルの高速化dp vl matmul(vl &dp, vvl &mt){ ll m=dp.size(); vl ret(m,0); rep(i,m)rep(j,m){ ret[i]+=mt[i][j]*dp[j]; ret[i]%=mod; } return ret; } vvl update(vvl &mt){ ll m=mt.size(); vvl ret(m,vl(m,0)); rep(i,m)rep(j,m)rep(k,m){ ret[i][j]+=mt[i][k]*mt[k][j]; ret[i][j]%=mod; } return ret; } void matpow(vl &dp, vvl &mt, ll k){ ll m=dp.size(); while(k){ if(k&1)dp=matmul(dp,mt); mt=update(mt); k/=2; } } ll modpow(ll a,ll n, ll mod) { ll res = 1; while (n > 0) { if (n & 1) res = res * a % mod; a = a * a % mod; n >>= 1; } return res; } void solve(){ ll n;cin >> n; ll inv=modpow(3,mod-2,mod); vvl mat(4,vl(4)); rep(i,2)mat[i+2][i]=1; mat[0][0]=inv; mat[0][3]=inv; mat[1][1]=inv; mat[1][2]=inv*2%mod; mat[1][3]=inv; vl dp(4);dp[0]=inv;dp[2]=1; matpow(dp,mat,n); cout << dp[2] << endl; } int main(){ ll t;cin >> t; while(t--)solve(); }