#include<bits/stdc++.h>
using namespace std;
#define rep(i,n) for(ll i=0;i<n;i++)
#define repl(i,l,r) for(ll i=(l);i<(r);i++)
#define per(i,n) for(ll i=(n)-1;i>=0;i--)
#define perl(i,r,l) for(ll i=r-1;i>=l;i--)
#define fi first
#define se second
#define pb push_back
#define ins insert
#define pqueue(x) priority_queue<x,vector<x>,greater<x>>
#define all(x) (x).begin(),(x).end()
#define CST(x) cout<<fixed<<setprecision(x)
#define vtpl(x,y,z) vector<tuple<x,y,z>>
#define rev(x) reverse(x);
using ll=long long;
using vl=vector<ll>;
using vvl=vector<vector<ll>>;
using pl=pair<ll,ll>;
using vpl=vector<pl>;
using vvpl=vector<vpl>;
const ll MOD=1000000007;
const ll MOD9=998244353;
const int inf=1e9+10;
const ll INF=4e18;
const ll dy[9]={0,1,-1,0,1,1,-1,-1,0};
const ll dx[9]={1,0,0,-1,1,-1,1,-1,0};
template<class T> inline bool chmin(T& a, T b) {
    if (a > b) {
        a = b;
        return true;
    }
    return false;
}
template<class T> inline bool chmax(T& a, T b) {
    if (a < b) {
        a = b;
        return true;
    }
    return false;
}


ll mod=1000000007;//一次元ベクトルの高速化dp
vl matmul(vl &dp, vvl &mt){
    ll m=dp.size();
    vl ret(m,0); 
    rep(i,m)rep(j,m){
        ret[i]+=mt[i][j]*dp[j];
        ret[i]%=mod;
    }
    return ret;
}
vvl update(vvl &mt){
    ll m=mt.size();
    vvl ret(m,vl(m,0));
    rep(i,m)rep(j,m)rep(k,m){
        ret[i][j]+=mt[i][k]*mt[k][j];
        ret[i][j]%=mod;
    }
    return ret;
}
void matpow(vl &dp, vvl &mt, ll k){
    ll m=dp.size();
    while(k){
        if(k&1)dp=matmul(dp,mt);
        mt=update(mt);
        k/=2;
    }
}

ll modpow(ll a,ll n, ll mod) {
  ll res = 1;
  while (n > 0) {
      if (n & 1) res = res * a % mod;
      a = a * a % mod;
      n >>= 1;
  }
  return res;
}

void solve(){
    ll c;cin >> c;
    ll n;cin >> n;
    ll m;cin >> m;
    ll inv=modpow(c,mod-2,mod);
    vvl mat(4,vl(4));
    rep(i,2)mat[i+2][i]=1;
    mat[0][0]=inv;
    mat[0][3]=inv;
    mat[1][1]=inv;
    mat[1][2]=inv*(c-1)%mod;
    mat[1][3]=inv*(c-2)%mod;
    vl dp(4);dp[0]=inv;dp[2]=1;
    matpow(dp,mat,n);
    //cout << dp[2] << endl;
    ll p=dp[2];
    p=((1-p)%mod+mod)%mod;
    p=modpow(p,m,mod);
    cout << ((1-p)%mod+mod)%mod << endl;
}
int main(){
    solve();
}