#include using namespace std; #define ll long long #define rep(i,n) for(int i=0;i #define Tp tuple #define all(v) v.begin(),v.end() #define riano_ std::ios::sync_with_stdio(false);std::cin.tie(nullptr);typedef modint mint using Graph = vector>; const ll mod = 998244353; template struct modint{ uint64_t val; constexpr modint(const int64_t val_=0) noexcept:val((val_%int64_t(mod)+int64_t(mod))%int64_t(mod)){} constexpr modint operator-() const noexcept{ return modint(*this)=mod-val; } constexpr modint operator+(const modint rhs) const noexcept{ return modint(*this)+=rhs; } constexpr modint operator-(const modint rhs) const noexcept{ return modint(*this)-=rhs; } constexpr modint operator*(const modint rhs) const noexcept{ return modint(*this)*=rhs; } constexpr modint operator/(const modint rhs) const noexcept{ return modint(*this)/=rhs; } constexpr modint &operator+=(const modint rhs) noexcept{ val+=rhs.val; val-=((val>=mod)?mod:0); return (*this); } constexpr modint &operator-=(const modint rhs) noexcept{ val+=((val>=1; } return (*this)*=now; } constexpr bool operator==(const modint rhs) noexcept{ return val==rhs.val; } constexpr bool operator!=(const modint rhs) noexcept{ return val!=rhs.val; } friend constexpr ostream &operator<<(ostream& os,const modint x) noexcept{ return os<<(x.val); } friend constexpr istream &operator>>(istream& is,modint& x) noexcept{ uint64_t t; is>>t,x=t; return is; } }; //累乗 aのb乗、正しmを法として求める long long pw(long long a,long long b,long long m){ if(b==0) return 1; else if(b%2==0){ long long x = pw(a,b/2,m); return (x*x)%m; } else{ long long x = pw(a,b-1,m); return (a*x)%m; } } //mod逆元 long long modinv(long long a, long long m) { long long b = m, u = 1, v = 0; while (b) { long long t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v); } u %= m; if (u < 0) u += m; return u; } ll ranmod(ll l,ll r,ll d,ll N){ ll res = ((pw(10,r-l+1,mod)-1*d%mod)*pw(10,N-r,mod)%mod)*modinv(9,mod)%mod; //cout << (pw(10,r-l+2,mod)-1*d%mod)*pw(10,N-r,mod)%mod << endl; return res; } // 最大公約数を求める ll gcd(ll x,ll y){ ll r=1; if(x<0) x *= -1; if(y<0) y *= -1; if(x<=y) swap(x,y); if(y==0) r=0; while(r>0){ r=x%y; x=y; y=r; } return x; } //Cの計算 C[i][j]でiCjを得る void combination(vector > &v){ for(int i = 0;i > T; rep(ii,T){ ans = "No"; ll N; cin >> N; vector org; rep(i,N){ org.push_back(i+1); } rep(i,N){ org.push_back(i+1); } vector> s(N+1,org); rep(i,N){ auto itr1 = s[i].begin(); auto itr2 = s[i].begin(); rep(j,i) itr1++; rep(j,N+1+i) itr2++; reverse(itr1,itr2); } vector a; rep(i,2*N){ ll b; cin >> b; a.push_back(b); } rep(i,N+1){ if(a==s[i]) ans = "Yes"; } cout << ans << "\n"; } }