# グラフの連結成分解法

from collections import deque
#==================================================
T=int(input())
N,C=map(int,input().split())

Power=[1<<i for i in range(2*N)]

# (1) 2π/N 回転
t=[0]*(2*N)
for j in range(N):
    t[j]  =(1+j)%N
    t[j+N]=t[j]+N

# (2) ひっくり返す
u=[0]*(2*N)
for j in range(N):
    u[j+N]=(0-j)%N
    u[j]  =u[j+N]+N

#==================================================
X=0
Seen=[0]*(4**N)

for A in range(4**N):
    if Seen[A]==0:
        X+=1

    Q=deque([A]); Seen[A]=1

    while Q:
        A=Q.popleft()

        # σ
        B=0
        for i in range(2*N):
            if (A>>i)&1:
                B|=Power[t[i]]

        if Seen[B]==0:
            Seen[B]=1
            Q.append(B)

        # τ
        C=0
        for i in range(2*N):
            if (A>>i)&1:
                C|=Power[u[i]]

        if Seen[C]==0:
            Seen[C]=1
            Q.append(C)

print(X)