#!/usr/bin/env python3

from pprint import pprint
from sys import setrecursionlimit, stdin
from typing import Dict, Iterable, Set

INF: int = 1 << 62
setrecursionlimit(1_000_000)


def inputs(type_=int):
    ins = input().split()

    if isinstance(type_, Iterable):
        return [t(x) for t, x in zip(type_, ins)]
    else:
        return list(map(type_, ins))


def input_(type_=int):
    a, = inputs(type_)
    return a


inputi = input_


def inputstr():
    return input_(str)


def answer(res) -> None:
    print(res)
    exit()

def isqrt(n):
    """
    計算量はO(log(n))以下である. (O(loglog(n))?)
    Ref: http://www.ritsumei.ac.jp/se/~osaka/rejime/suuti/suuti2001.pdf
    """
    x, y = n, (n + 1) // 2
    while y < x:
        x, y = y, (y + n // y) // 2
    return x

# start coding
t = inputi()
for i in range(t):
    x = inputi()
    print(isqrt(x))