#include #include using namespace std; using namespace atcoder; using mint = modint998244353; //using mint = modint1000000007; using ll = long long; using ld = long double; using pll = pair; using tlll = tuple; constexpr ll INF = 1LL << 60; template bool chmin(T& a, T b) {if (a > b) {a = b; return true;} return false;} template bool chmax(T& a, T b) {if (a < b) {a = b; return true;} return false;} ll safemod(ll A, ll M) {return (A % M + M) % M;} ll divfloor(ll A, ll B) {if (B < 0) {return divfloor(-A, -B);} return (A - safemod(A, B)) / B;} ll divceil(ll A, ll B) {if (B < 0) {return divceil(-A, -B);} return divfloor(A + B - 1, B);} #define FINALANS(A) do {cout << (A) << '\n'; exit(0);} while (false) int main() { ll N; cin >> N; const ll M = 1000000; vector B(M + 1); for (ll i = 0; i < N; i++) { ll a; cin >> a; B.at(a)++; } vector cnt(M + 1, 0); for (ll d = 1; d <= M; d++) { for (ll k = 1; k * d <= M; k++) { cnt.at(d) += B.at(k * d); } } vector ans(N + 1); ll tmp = 0; for (ll g = M; g >= 1; g--) { if (cnt.at(g) > tmp) { for (ll i = tmp + 1; i <= cnt.at(g); i++) { ans.at(i) = g; } tmp = cnt.at(g); } } for (ll i = N; i >= 1; i--) { cout << ans.at(i) << endl; } }