#ぱっと思いつくのはdp[i][j] = i番目まで見て積をkで割ったあまりがjになるものの個数　無理
#Kの約数で考える? K <= 10^9からもそれっぽい
n, k = map(int,input().split())
mod = 10 ** 9 + 7
from collections import Counter
import copy
a = list(map(int,input().split()))
#ありがとう
def div(N):
    ret = []
    for i in range(2, N + 1):
        if i * i > N:
            break
        if N % i == 0:
            ret.append(i)
            if i != N // i:
                ret.append(N // i)
    return ret

d = div(k)
dp = Counter()
for i in d:
    dp[i] = 0
dp[1] = 1
from math import gcd
for i in range(n):
    E = dp
    dp = Counter()
    for v in E.keys():
        dp[gcd(k, v * a[i])] += E[v]
        dp[v] += E[v]
        dp[gcd(k, v * a[i])] %= mod
        dp[v] %= mod

print((dp[k] + dp[0] +(-1 if k == 1 else 0)) % mod)